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Feliz [49]
3 years ago
15

To eight significant figures, avogadro's constant is 6.0221367×1023mol−1. which of the following choices demonstrates correct ro

unding?

Chemistry
2 answers:
Paha777 [63]3 years ago
6 0

All of the following choices demonstrates correct rounding

<h3>Further explanation</h3>

There are general rules used in rounding numbers

  • 1. Determine the rounded digit
  • 2. Pay attention to the digits afterward (right). If the digit shows the numbers 0, 1, 2, 3 or 4, then the digit to be rounded is fixed, and the digit on the right is 0
  • 3. If the digit on the right shows the numbers 5, 6, 7, 8 or 9, then the digit to be rounded is added to one, and the digit on the right side is made all 0

for example, In rounding the nearest hundreds number, then we see the digit in the number tens (right of the digit hundreds), if it is worth 0, 1, 2, 3 or 4, then it remains, but if it shows numbers 5, 6, 7, 8 or 9, then the digit to be rounded is added one, and the right-hand side is 0

Choice of answer we add from the problem above:

6,022 × 10²³mol⁻¹

6.0 × 10²³mol⁻¹

6,02214 × 10²³mol⁻¹

For the Avogadro number of 6.0221367 × 10²³mol⁻¹

  • 1. If we round into a 4 digit significant number, we see the digit after the number from the 4th digit of the 6.022 number (i.e. 2)

After this 4th digit we see number 1 so the rounding remains to be: 6,022

  • 2. For Avogadro numbers on rounding to 2 digits, because the number after 0 at number 6.0 is 2 then the rounding is fixed so that it is worth 6.0
  • 3. For Avogadro numbers in rounding to 6 digits, because the number after 3 at number 6.0221367 is 6 then rounding up so that it is worth 6.02214

So all of the answer choices are correct

<h3>Learn more</h3>

five numbers that are round up and round down to 600

brainly.com/question/258166

all the numbers that round to 50

brainly.com/question/136503

round 4,398,202 to the nearest 100

brainly.com/question/640968

Round number 4278649 to nearest 100

brainly.com/question/829024

Keywords: round up, round down, the rounded digit

FrozenT [24]3 years ago
5 0
6.0221367 rounded from the last digit would be 6.022137 but when using it calculations, you should just use 6.022 x 10^23.  
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2 years ago
Given the following thermodynamic data, calculate the lattice energy of LiCl:
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Answer:

\boxed{\text{-862 kJ/mol}}

Explanation:

One way to calculate the lattice energy is to use Hess's Law.

The lattice energy U is the energy released when the gaseous ions combine to form a solid ionic crystal:

Li⁺(g) + Cl⁻(g) ⟶ LiCl(s); U = ?

We must generate this reaction rom the equations given.

(1)  Li(s) + ½Cl₂ (g) ⟶ LiCl(s);      ΔHf°     = -409 kJ·mol⁻¹

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(3) Cl₂(g) ⟶ 2Cl(g)                     BE        =   243 kJ·mol⁻¹

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(5) Cl(g) + e⁻ ⟶ Cl⁻(g)                EA₁       =  -349 kJ·mol⁻¹

Now, we put these equations together to get the lattice energy.

                                                <u>E/kJ </u> 

(5) Li⁺(g) +e⁻ ⟶ Li(g)                520

(6) Li(g) ⟶ Li(s)                         -161

(7) Li(s) + ½Cl₂(g) ⟶ LiCl(s)     -409

(8) Cl(g) ⟶ ½Cl₂(g)                   -121.5

(9) Cl⁻(g) ⟶ Cl(g) + e⁻               <u>+349</u>

      Li⁺(g) +  Cl⁻(g) ⟶ LiCl(s)     -862

The lattice energy of LiCl is \boxed{\textbf{-862 kJ/mol}}.

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