Question

For a given launch velocity, at which launch angle does the projectile undergo the maximum horizontal displacement?

Answer 1

Answer: option B. 45°

Explanation:

A body thrown at an angle from horizontal undergoes a projectile motion. The maximum horizontal displacement means the maximum range covered. The range is given by:

$R = \frac{v^2 sin 2\theta}{g}$

where v is the initial velocity, $\theta$ is angle of the projectile and g is the acceleration due to gravity.

For maximum range, sin 2θ = 1

2θ = sin⁻¹ 1 = 90°

θ = 90°/2 = 45°

Thus, the projectile undergoes maximum horizontal displacement at angle of 45°. Correct option is B.