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Marat540 [252]
3 years ago
13

Two point charges, initially 1 cm apart, are moved to a distance of 3 cm apart. By what factor do the resulting electric and gra

vitational forces between them change?
a.9
c.1/3
b.3
d.1/4
Physics
1 answer:
s2008m [1.1K]3 years ago
6 0
Answer: 1/9

Explanation:

As per Coulomb Law, electric force, is inversely related to the square of the distance that separate them., when other factors remain constant.

That means, Electrical force α 1/d^2, => Electrical force = k / d^2

Call FE the electrical force when d = 1 cm => FE = k / (1cm)^2

Call FE' the electrical force when d = 3cm => FE' = k / (3cm)^2

=> k = FE(1cm)^2 = FE'(9cm)^2 => FE' = FE / 9

As per Universal Gravitational Law, discovered by Sir Isacc Newton, the gravitational force between two objects is inversely related to the square of the distance that separate them, so you get the same relation between the gravitational force and the distance as you found for the electric force,i.e  gravitational force α 1/d^2, with which you will obtain the same factor for the case given: 1/9.
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For a caffeinated drink with a caffeine mass percent of 0.65% and a density of 1.00 g/mL, how many mL of the drink would be requ
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Explanation:

First we will convert the given mass from lb to kg as follows.

        157 lb = 157 lb \times \frac{1 kg}{2.2046 lb}

                   = 71.215 kg

Now, mass of caffeine required for a person of that mass at the LD50 is as follows.

         180 \frac{mg}{kg} \times 71.215 kg

         = 12818.7 mg

Convert the % of (w/w) into % (w/v) as follows.

      0.65% (w/w) = \frac{0.65 g}{100 g}

                           = \frac{0.65 g}{(\frac{100 g}{1.0 g/ml})}

                           = \frac{0.65 g}{100 ml}

Therefore, calculate the volume which contains the amount of caffeine as follows.

   12818.7 mg = 12.8187 g = \frac{12.8187 g}{\frac{0.65 g}{100 ml}}

                       = 1972 ml

Thus, we can conclude that 1972 ml of the drink would be required to reach an LD50 of 180 mg/kg body mass if the person weighed 157 lb.

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