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faltersainse [42]
2 years ago
8

Points a and b are nearby a proton in otherwise empty space. the potential is chosen to be zero very far away from the proton. t

he potential at a is half as much as the potential at b. compared to the electric field energy density at b, the electric field energy density at a is __
Physics
1 answer:
sertanlavr [38]2 years ago
3 0

Compared to the electric field energy density at b, the electric field energy density at a is large by a factor of 16.

<h3>What is potential energy?</h3>

The energy of a particle by virtue of its position.

The potential at B = Vb =V

Vb = 1/4π∈₀ x e/r₁ = ke/r₁

V =ke/r₁

and r₁ = ke /V

The potential at A = Va = 2V

2V = ke/r₂

r₂ = ke/2V

The electric field at point B. Eb = ke/r₁²

Substitute the value of r₁, we get

Eb = V²/ke

The electric field at point A , Ea = ke /r₂²

Substitute the value of r₂, we get

Ea = 4V²/ke


The electric field energy density at point A and B,

Ua  = 1/2 ∈Ea²

Ub = 1/2 ∈Eb²

electric field energy density is proportional to the square of electric field at the particular point.

Ua/Ub =(Ea/Eb)²

Substitute the values, we get

Ua/Ub = 16

Thus, compared to the electric field energy density at b, the electric field energy density at a is large by a factor of 16.

Learn more about potential energy.

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Giving a test to a group of students, the grades and gender are summarized belowGrades vs. Gender ABCMale10316Female465If one st
strojnjashka [21]

Answer:

20.45%

Explanation:

The probability that the student got a B is

\frac{total\#of\text{ students that got B}}{\text{total students }}\times100\%

Now, how many students are there in total?

The answer is

10+3+16+4+6+5=44\; \text{students}

How many students got a B?

The answer is

3+6=9\; \text{students}

therefore, the probability that the student has got a B is

\frac{9\text{ students }}{44\text{ students }}\times100\%=20.45\%

Hence, the probability that a student has got a B is 20.45%

5 0
1 year ago
A book is on the table. If the weight of the book is 25 newtons, what is the magnitude and direction of the normal force?
Andrej [43]
I'm not sure about the magnitude, but the direction of the normal force is upward. 
4 0
3 years ago
Read 2 more answers
A wave is traveling through a medium ad it travels it displaces particles of matter in the same direction as the wave is traveli
Tamiku [17]
I think it's longitudinal wave because the particles move parallel to the direction that the wave is traveling. 
7 0
3 years ago
Read 2 more answers
Sound level B in decibels is defined as
Lelechka [254]

Answer:

The approximate combined sound  intensity is I_{T}=1.1\times10^{-4}W/m^{2}

Explanation:

The decibel  scale intensity for busy traffic is 80 dB. so intensity will be

10log(\frac{I_{1}}{I_{0}} )=80, therefore I_{1}=1\times10^{8}I_{0}=1\times10^{8} * 1\times10^{-12}W/m^{2}=1\times10^{-4}W/m^{2}

In the same way for the loud conversation having a decibel intensity of 70 dB.

10log(\frac{I_{2}}{I_{0}} )=70, therefore I_{2}=1\times10^{7}I_{0}=1\times10^{7} * 1\times10^{-12}W/m^{2}=1\times10^{-5}W/m^{2}

Finally we add both of them I_{T}=I_{1}+I_{2}=1\times10^{-4}W/m^{2}+1\times10^{-5}W/m^{2}=1.1\times10^{-4}W/m^{2}, is the approximate combined sound  intensity.

3 0
3 years ago
A series of pulses, each of amplitude 0.1m , is sent down a string that is attached to a post at one end. The pulses are reflect
sp2606 [1]

The net displacement at a point on the string where the pulses cross is 0.2 m.

The term "displacement" refers to a shift in an object's position. It has a magnitude and a direction, making it a vector quantity. An arrow pointing from the starting point to the finishing point serves as its symbol.

A string that is connected to a post at one end is used to transmit a sequence of pulses, each measuring 0.1 meters in amplitude.

At the post, the pulses are reflected and return along the string without losing any of their amplitude.

Now, let's say the ends are free.

There is no inversion on reflection if the end is free. The amplitude at their intersection is 2A.

Now, since A = 0.1 m

Then, 2A = 2(0.1) = 0.2 m

As a result, the net displacement at the string's intersection of two pulses is 0.2 m.

The correct option is (c).

Learn more about amplitude here:

brainly.com/question/3613222

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4 0
2 years ago
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