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faltersainse [42]
2 years ago
8

Points a and b are nearby a proton in otherwise empty space. the potential is chosen to be zero very far away from the proton. t

he potential at a is half as much as the potential at b. compared to the electric field energy density at b, the electric field energy density at a is __
Physics
1 answer:
sertanlavr [38]2 years ago
3 0

Compared to the electric field energy density at b, the electric field energy density at a is large by a factor of 16.

<h3>What is potential energy?</h3>

The energy of a particle by virtue of its position.

The potential at B = Vb =V

Vb = 1/4π∈₀ x e/r₁ = ke/r₁

V =ke/r₁

and r₁ = ke /V

The potential at A = Va = 2V

2V = ke/r₂

r₂ = ke/2V

The electric field at point B. Eb = ke/r₁²

Substitute the value of r₁, we get

Eb = V²/ke

The electric field at point A , Ea = ke /r₂²

Substitute the value of r₂, we get

Ea = 4V²/ke


The electric field energy density at point A and B,

Ua  = 1/2 ∈Ea²

Ub = 1/2 ∈Eb²

electric field energy density is proportional to the square of electric field at the particular point.

Ua/Ub =(Ea/Eb)²

Substitute the values, we get

Ua/Ub = 16

Thus, compared to the electric field energy density at b, the electric field energy density at a is large by a factor of 16.

Learn more about potential energy.

brainly.com/question/24284560

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Michael's house is 5.0 km away from his school. How long would it take him to go ti school, riding a bus, if its velocity is 25
Anvisha [2.4K]

Answer:

12 mins

Explanation:

The distance covered is 5 km, divide this by 25 to get the fraction of an hour it takes. Doing this you get .2, times this by 60 min (1 hour) to get how many mins it takes

8 0
3 years ago
How do earthquakes affect earths surface?
ivanzaharov [21]
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4 0
4 years ago
Two canoeists in identical canoes exert the same effort paddling and hence maintain the same speed relative to the water. One pa
Serga [27]

Answer:

Speed of river is 0.45 m/s

Speed of boat is 2.65 m/s

Explanation:

v_r = Speed of river

v_c = Speed of canoe

v_r+v_c=2.8\ m/s

v_r-v_c=-1.9\ m/s

Adding the equations we get

2v_r=0.9\\\Rightarrow v_r=\frac{0.9}{2}\\\Rightarrow v_r=0.45\ m/s

0.42+v_c=2.8\ m/s\\\Rightarrow v_c=2.8-0.45\\\Rightarrow v_c=2.65\ m/s

Speed of river is 0.45 m/s

Speed of boat is 2.65 m/s

6 0
3 years ago
If one of two interacting charges is doubled, the force between the charges will _____________.
malfutka [58]

If one of two interacting charges is doubled, the force between the charges will double.

Explanation:

The force between two charges is given by Coulomb's law

F=\frac{k q1 q2}{r^{2}}

K=constant= 9 x 10⁹ N m²/C²

q1= charge on first particle

q2= charge on second particle

r= distance between the two charges

Now if the first charge is doubled,

we get F'=\frac{k (2q1) q2}{r^{2}}

F'= 2 F

Thus the force gets doubled.

4 0
3 years ago
I need help answering 30A and B. Help a guy out?
dmitriy555 [2]

Uh so I'm no master at this subject, but all stuffs accelerate at 9.8 m/s squared. So you multiply the 9.8 and the 0.20 it's given for reasons unknown other than that's what I see in my notes... and that gives you 1.96 m/s squared.

As for B, I have no idea. I think you may multiply the 1.96 by 4. Tell me your thoughts and maybe we can work it out together

5 0
3 years ago
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