How many solutions exist for the given equation?
1 answer:
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Note: Consider we need to find the vertices of the triangle A'B'C'
Given:
Triangle ABC is rotated 90 degrees clockwise about the origin to create triangle A'B'C'.
Triangle A,B,C with vertices at A(-3, 6), B(2, 9), and C(1, 1).
To find:
The vertices of the triangle A'B'C'.
Solution:
If triangle ABC is rotated 90 degrees clockwise about the origin to create triangle A'B'C', then
Using this rule, we get
Therefore, the vertices of A'B'C' are A'(6,3), B'(9,-2) and C'(1,-1).
Answer:
<em>The firefighter should extend the ladder at 54° of elevation.</em>
Step-by-step explanation:
<u>Trigonometric Ratios</u>
The ratios of the sides of a right triangle are called trigonometric ratios. There are six trigonometric ratios, sine, cosine, tangent, cosecant, secant, and cotangent.
The longest side of the triangle is called the hypotenuse and the other two sides are the legs.
Selecting any of the acute angles as a reference, it has an adjacent side and an opposite side. The trigonometric ratios are defined upon those sides.
<em>Tangent Ratio:</em>
The woman is trapped at 91 feet up from the ground, and the firetruck is 67 feet away from the building.
The wall, the ground, and the ladder form a right triangle, where θ is the horizontal angle of the ladder.
Being the height of the woman the opposite leg and the distance where the firetruck is parked, the adjacent leg:
The angle is calculated as the inverse tangent:
The firefighter should extend the ladder at 54° of elevation.