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3 years ago

What happens to a reaction at equilibrium when a product is removed from the reaction system?

Chemistry

2 answers:

Naily [24]3 years ago

6 0

Answer : The correct option is, (a) the reaction makes more products.

Explanation :

Le-Chatelier's principle : This principle states that if any change in the variables of the reaction, the equilibrium will shift in the direction to minimize the effect.

When a product is removed from the reaction system :

If the product is removed from the reaction then amount of reactant increases and product decrease. The equilibrium will shift in the direction where decrease in the amount takes palace. As, the amount is decreasing on product side. So, equilibrium will shift in the right direction that means in product side.

Hence, the correct option is, (a)

adoni [48]3 years ago

5 0

C. the reaction is unchanged.

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A company wants to sell more sports drinks so they decide to add more sugar. For Group A they

ycow [4]

Answer:

Group B

Explanation:

The control group of an experiment is considered to be the "normal" because it does not receive the expeiemental treatment and hence is used to compare with the experimental group. The control and experimental groups are similar in every other aspect with the exception of the "INDEPENDENT VARIABLE". The independent variable is not changed in the control group.

In this experiment, the control group is GROUP B, which was given a plain gatorade without adding sugar. Sugar is the independent variable here, and it was not included in GROUP B, meaning that GROUP B is the CONTROL GROUP. On the other hand, the experimental group is the GROUP A.

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3 years ago

If 90.0 grams of ethane reacted with excess chlorine,how many grams of dicarbon hexachloride would form

tigry1 [53]

Answer:

709 g

Step-by-step explanation:

a) Balanced equation

Normally, we would need a balanced chemical equation.

However, we can get by with a partial equation, as log as carbon atoms are balanced.

We know we will need an equation with masses and molar masses, so let’s <em>gather all the information</em> in one place.

M_r: 30.07 236.74

C₂H₆ + … ⟶ C₂Cl₆ + …

m/g: 90.0

(i) Calculate the moles of C₂H₆

n = 90.0 g C₂H₆ × (1 mol C₂H₆ /30.07 g C₂H₆)

= 2.993 mol C₂H₆

(ii) Calculate the moles of C₂Cl₆

The molar ratio is (1 mol C₂Cl₆/1 mol C₂H₆)

n = 2.993 mol C₂H₆ × (1 mol C₂Cl₆/1 mol C₂H₆)

= 2.993 mol C₂Cl₆

(iii) Calculate the mass of C₂Cl₆

m = 2.993 mol C₂Cl₆ × (236.74 g C₂Cl₆/1 mol C₂Cl₆)

m = 709 g C₂Cl₆

The reaction produces 709 g C₂Cl₆.

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3 years ago

What will happen to convection currents in the mantle if earths interior eventually cools down?

VLD [36.1K]

If the core were to cool completely, the planet would grow cold and dead. It also would get a little dark: Power utilities pull radiant heat from Earth's crust and use it to heat water, the steam from which powers turbines to create electricity.Cooling also could cost us the magnetic shield around the planet created by heat from the core. This shield protects Earth from cosmic radiation. The shield is created by a convection process caused by constantly moving iron. Like the planet itself, Earth's core is constantly spinning. Some scientists think it's moving even faster than the rest of the planet. The friction converts kinetic energy into electrical and magnetic energy that forms the field, which deflects harmful, charged particles emanating from the sun toward the north and south poles. Your welcome :)

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4 years ago

A chemistry student needs 15.0 g of methanol for an experiment. She has available 320. g of 44.4% w/w solution of methanol in wa

Makovka662 [10]

Answer:

33.8 g Solution

Explanation:

A chemistry student needs 15.0 g of methanol for an experiment. The concentration of ethanol in the solution is 44.4% w/w, that is, there are 44.4 g of methanol every 100 g of solution. The mass of solution that would contain 15.0 g of methanol is:

15.0 g Methanol × 100 g Solution/44.4 g Methanol = 33.8 g Solution

Since 33.8 g are required and 320. g are available, there is enough solution for the requirements.

4 0

3 years ago

New industrial plants for acetic acid react liquid methanol (Mm=32g/m) with carbon monoxide in the presen of a catalyst. In an e

Daniel [21]

Answer:

21.42 g

Explanation:

To know this, you need to put the equation that is taking and it's the following:

CH3OH (Methanol) + CO ---------> CH3COOH (Acetic acid)

We already know the mm of methanol, and the mm for CO is:

AM of C = 12 g/mol

AM of O = 16 g/mol

AM of H = 1 g/mol

MM of CO = 12 + 16 = 28 g/m

For acetic acid: 12 + 3(1) + 12 + 16*2 + 1 = 60 g/mol

Now that we know the molar mass of each molecule, let's calculate the number of moles of methanol and CO, because it's easier to work with moles than the grams

moles of methanol = 15/32 = 0.469 moles

moles of CO = 10/28 = 0.357 moles

According to the equation 1 mole of methanol reacts completely with 1 mole of CO. However, in this case, we can see that methanol exceed the CO, so, the CO is the limitant reactant so:

moles reactants of methanol: 0.469 - 0.357 = 0.112 moles.

moles of acid produced: 0.357 moles

This is because we have a ratio of 1:1 between methanol and CO. As methanol exceed CO, the CO is consumed completely leaving a remanant of methanol behind. the whole moles of CO are used, and appears as product of acetic acid, therefore, the moles of acetic acid are the same of CO.

Now with the molar mass of acid, let's calculate the gram of acid, and yield:

g = 0.357 * 60 = 21.42 g of acetic acid.

This is the theorical yield of acetic acid.

5 0

4 years ago