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My name is Ann [436]
2 years ago
12

A sled and rider with a combined mass of 70 kg are at the top of a hill that rises 9 m above the level ground below. The sled is

given a push, providing an initial kinetic energy at the top of the hill of 1,200 J. a. Choosing a reference level at the bottom of the hill, what is the potential energy of the sled and rider at the top of the hill? sled and rider at the top of the hill? of the sled and rider at the bottom of the hill? b. After the push, what is the total mechanical energy of the hill?c. If friction can be ignored, what will be the kinetic energy of the sled and rider at the bottom of the hill?

Physics
1 answer:
kvv77 [185]2 years ago
3 0

Answer:

(A) 6174J, 0J.

(B) 7374J

(C) 7374J

Explanation:

See the attachment below for the calculation.

The princi6of conservation of energy has been used.

E = K1 + U1 = K2 + U2

Where E = total mechanical energy.

Taking the bottom as reference, and h =0 and as a result U2 = mg(0) = 0J.

The complete solution to the problem can be found in the attachment below.

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Answer:

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Let's start looking for the stack speeds, it has a free fall, from rest  (Vo=0)

             

           Vf² = Vo² - 2gY

            Vf² = 0 - 2 9.8 7.69 = 150.7

            Vf = 12.3 m / s

This is the speed that the battery likes when it touches the beam.  They also give us the distance it travels before stopping, let's calculate the time

         

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             t = 1.26 s

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Now let's use the equation that relates the impulse to the amount of movement

                 I = Δp

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The amount of final movement is zero because the system stops

                F = - po / t

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                F = - 1150 12.3 / 1.26

                F = -11226 N

This is the average force exerted by the stack on the vean

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