Question

A 10-mm-diameter Brinell hardness indenter produced an indentation 1.55 mm in diameter in a steel alloy when a load of 500 kg was used. Calculate the Brinell hardness (in HB) of this material. Enter your answer in accordance to the question statement HB

Answer 1

Answer:

HB = 3.22

Explanation:

The formula to calculate the Brinell Hardness is given as follows:

$HB = \frac{2P}{\pi D\sqrt{D^{2}- d^{2} } }$

where,

HB = Brinell Hardness = ?

P = Applied Load in kg = 500 kg

D = Diameter of Indenter in mm = 10 mm

d = Diameter of the indentation in mm = 1.55 mm

Therefore, using these values, we get:

$HB = \frac{(2)(500)}{\pi (10)\sqrt{10^{2}- 1.55^{2} } }$

HB = 3.22