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2 years ago

Does anyone have cumulative exams today or tomorrow?(There so boring!)

Engineering

2 answers:

AlekseyPX2 years ago

6 0

Answer:

I feel bad for you

Explanation:

They are so overwhelming and boring

IRINA_888 [86]2 years ago

3 0

Answer:

I do!!

Explanation:

I have to sit for 3 hours lol‍♀️

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3 years ago

Help me my life is depending on this question... 2+2

BabaBlast [244]

Answer:4

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2 years ago

A displacement transducer has the following specifications Linearity error ±0.1% of reading, Drift ±0.15%/C of reading, sensitiv

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2 years ago

A drilling operation is to be performed with a 12.7 mm diameter drill on cast iron. The hole depth is 60 mm and the drill point

Gnoma [55]

Answer:

a. Tm = 0.3192min.

b. MRR = 396.91mm^{3}/s.

Explanation:

Given the following data;

Drill diameter, D = 12.7mm

Depth, L = 60mm

Cutting speed, V = 25m/min = 25,000m

Feed, F = 0.30mm/rev

To find the cutting time;

Cutting time, Tm =?

$Tm = \frac{L}{Fr}$ .......eqn 1

We would first solve for the feed rate (F);

$Fr = NF$ .......eqn 2

But we need to find the rotational speed (N);

$N= \frac{V}{\pi *D}$

$N= \frac{25000}{3.142*12.7}$

$N= \frac{25000}{39.90}$

N = 626.57rev/min.

Substiting N into eqn 2;

$Fr = NF$

Fr = 626.57 * 0.30

Fr = 187.97mm/min.

Substiting F into eqn 1;

$Tm = \frac{L}{Fr}$

$Tm = \frac{60}{187.97}$

Tm = 0.3192min.

Therefore, the cutting time is 0.3192 minutes.

For the material removal rate (MRR);

$MRR = \frac{\pi *D^{2}Fr}{4}$

$MRR = \frac{3.142*12.7^{2}*187.97}{4}$

$MRR = \frac{3.142*161.29*187.97}{4}$

$MRR = \frac{95258.16}{4}$

$MRR = 23814.54mm^{3}/min$

Time in seconds, we divide by 60;

MRR = 23814.54/60 =396.91mm^{3}/s.

Therefore, the material removal rate (MRR) is 396.91mm^{3}/s.

4 0

2 years ago

X − 3y − 8z = −10 2x + 5y + 6z = 13 3x + 2y − 2z = 3

nikitadnepr [17]

Answer:

x - 3y - 8z = -10 2x + 5y + 6z = 13 3x + 2y - 2z = 3 => (-1+2z,2-2z,z)

Explanation:

x - 3y - 8z = -10 2x + 5y + 6z = 13 3x + 2y - 2z = 3

Solve using Gaussian Elimination

7 0

1 year ago