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nordsb [41]
3 years ago
10

_____ braking is when you squeeze the brake pedal until just before the wheels lock, then ease off the pedal, then squeeze again

, repeating until you've reduced your speed enough.
A. Traditional
B. Power
C. ABS
D. Threshold
Engineering
2 answers:
grin007 [14]3 years ago
6 0
The answer should be d) threshold
frozen [14]3 years ago
6 0

Answer:

abs

Explanation:

i took the class

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What is a thermal reservoir?
Mekhanik [1.2K]

Answer:

Explanation:

Thermal reservoir:

   It is the body which have infinite amount of heat capacity and store large amount of heat.The temperature of thermal reservoir is constant and does not change with time.The temperature of thermal reservoir is not change even heat is going out from reservoir or heat going inside the reservoir.The temperature of thermal reservoir remains constant and does not depend on the surroundings.

7 0
4 years ago
What similarities do wind and solar energy share?
Viefleur [7K]

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Both come from the sun

Both are reusable sources

and both don't cause pollution

Explanation:

3 0
2 years ago
If you detect that something’s wrong while lowering a lift, you should try to get the vehicle down as fast as possible
Rashid [163]
False, it depends on the situation. If the lift is tilting or anything like I would then get down. Certain training will say to get out and see if you can keep lowering,
4 0
3 years ago
Do you notice differences in aerosol concentration at different latitudes
Papessa [141]

Answer:

Aerosol Concentrations in Relationship to Local Atmospheric Conditionsation:

Explan

5 0
3 years ago
The 30-kg gear is subjected to a force of P=(20t)N where t is in seconds. Determine the angular velocity of the gear at t=4s sta
tatyana61 [14]

Answer:

\omega =\frac{24}{1.14375}=20.983\frac{rad}{s}

Explanation:

Previous concepts

Angular momentum. If we consider a particle of mass m, with velocity v, moving under the influence of a force F. The angular  momentum about point O is defined as the “moment” of the particle’s linear momentum, L, about O. And the correct formula is:

H_o =r x mv=rxL

Applying Newton’s second law to the right hand side of the above equation, we have that r ×ma = r ×F =

MO, where MO is the moment of the force F about point O. The equation expressing the rate of change  of angular momentum is this one:

MO = H˙ O

Principle of Angular Impulse and Momentum

The equation MO = H˙ O gives us the instantaneous relation between the moment and the time rate of change of angular  momentum. Imagine now that the force considered acts on a particle between time t1 and time t2. The equation MO = H˙ O can then be integrated in time to obtain this:

\int_{t_1}^{t_2}M_O dt = \int_{t_1}^{t_2}H_O dt=H_0t2 -H_0t1

Solution to the problem

For this case we can use the principle of angular impulse and momentum that states "The mass moment of inertia of a gear about its mass center is I_o =mK^2_o =30kg(0.125m)^2 =0.46875 kgm^2".

If we analyze the staritning point we see that the initial velocity can be founded like this:

v_o =\omega r_{OIC}=\omega (0.15m)

And if we look the figure attached we can use the point A as a reference to calculate the angular impulse and momentum equation, like this:

H_Ai +\sum \int_{t_i}^{t_f} M_A dt =H_Af

0+\sum \int_{0}^{4} 20t (0.15m) dt =0.46875 \omega + 30kg[\omega(0.15m)](0.15m)

And if we integrate the left part and we simplify the right part we have

1.5(4^2)-1.5(0^2) = 0.46875\omega +0.675\omega=1.14375\omega

And if we solve for \omega we got:

\omega =\frac{24}{1.14375}=20.983\frac{rad}{s}

8 0
3 years ago
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