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ratelena [41]
3 years ago
12

The 0.5-kg collar C starts from rest at A and slides with negligible friction on the fixed rod in the vertical plane. Determine

the velocity v with which the collar strikes end B when acted upon by the 5-N force, which is constant in direction. Neglect the small dimensions of the collar. [Use Principle of energy conservation]
Engineering
1 answer:
xxMikexx [17]3 years ago
6 0

Answer:

The answer is 2.32 m/s

Explanation:

Solution

Given that:

U a-b = ΔT

Thus

F cos 30° * hₐ - F sin 30° * hₐ + Whₐ = 1/2 m (v²b - v²ₐ)

Now,

vb =√2Fhₐ (cos 30° - sin 30°)+ mghₐ/ m + v²ₐ

Where

F = This is the force acting on the collar

m = this is the mass on the collar C

g = The acceleration due to gravity

hₐ = The height of the collar at the position A

vb = The velocity of the collar at position B

vₐ = The velocity of the collar at A

So,

We replace 5N for F, 0.2 m for hₐ, 0.5 kg for m, 9.81 m/s for g, 0 for vₐ

Now,

vb =√ 2 * (5 *0.2 * ( cos 30° - sin 30°) +0.5 * 9.81 * 0.2 / 0.5 + 0

=√2.694/0.5

=2.32 m/s

Hence, the he velocity v with which the collar strikes the end B is 2.32 m/s

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Answer:

Write all notes in google docs

Explanation:

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3 years ago
How many meters per second is 100 meters and 10 seconds
Elden [556K]

Answer:

the velocity = 10 m / sec if an object moves 100 m in 10s

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2 years ago
Create an abstract class DiscountPolicy. It should have a single abstract method computeDiscount that will return the discount f
eimsori [14]

Answer:

Java Code was used to define classes in the abstract discount policy,The bulk discount, The buy items get one free and the combined discount

Explanation:

Solution

Code:

Main.java

public class Main {

public static void main(String[] args) {

  BulkDiscount bd=new BulkDiscount(10,5);

BuyNItemsGetOneFree bnd=new BuyNItemsGetOneFree(5);

CombinedDiscount cd=new CombinedDiscount(bd,bnd);

System.out.println("Bulk Discount :"+bd.computeDiscount(20, 20));

  System.out.println("Nth item discount :"+bnd.computeDiscount(20, 20));

 System.out.println("Combined discount :"+cd.computeDiscount(20, 20));    

  }

}

discountPolicy.java

public abstract class DiscountPolicy

{    

public abstract double computeDiscount(int count, double itemCost);

}    

BulkDiscount.java  

public class BulkDiscount extends DiscountPolicy

{    

private double percent;

private double minimum;

public BulkDiscount(int minimum, double percent)

{

this.minimum = minimum;

this.percent = percent;

}

at Override

public double computeDiscount(int count, double itemCost)

{

if (count >= minimum)

{

return (percent/100)*(count*itemCost); //discount is total price * percentage discount

}

return 0;

}

}

BuyNItemsGetOneFree.java

public class BuyNItemsGetOneFree extends DiscountPolicy

{

private int itemNumberForFree;

public BuyNItemsGetOneFree(int n)

{

  itemNumberForFree = n;

}

at Override

public double computeDiscount(int count, double itemCost)

{

if(count > itemNumberForFree)

return (count/itemNumberForFree)*itemCost;

else

  return 0;

}

}

CombinedDiscount.java

public class CombinedDiscount extends DiscountPolicy

{

private DiscountPolicy first, second;

public CombinedDiscount(DiscountPolicy firstDiscount, DiscountPolicy secondDiscount)

{

first = firstDiscount;

second = secondDiscount;

}

at Override

public double computeDiscount(int count, double itemCost)

{

double firstDiscount=first.computeDiscount(count, itemCost);

double secondDiscount=second.computeDiscount(count, itemCost);

if(firstDiscount>secondDiscount){

  return firstDiscount;

}else{

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}  

}

6 0
3 years ago
What is one major life lesson you learned from the movie; ¨Spare Parts¨
allochka39001 [22]

Answer:

darts,” a smart, creative and highly-enjoyable drama about a team of intelligent, hard-working and ambitious high school students who enter a prestigious robotics competition, and their dedicated science teacher who mentors, educates, pushes and inspires them, is a rousing, uplifting, spirited–and excellent–film and a great start to the new film

6 0
3 years ago
Read 2 more answers
A tank with a volume of 8 m3 containing 4 m3 of 20% (by volume) NaOH solution is to be purged by adding pure water at a rate of
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Answer:

The time necessary to purge 95% of the NaOH is 0.38 h

Explanation:

Given:

vfpure water(i) = 3 m³/h

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vfpure water(f) = 2 m³/h

pwater = 1000 kg/m³

pNaOH = 1220 kg/m³

The mass flow rate of the water is = 3 * 1000 = 3000 kg/h

The mass of NaOH in the solution is = 0.2 * 4 * 1220 = 976 kg

When the 95% of the NaOH is purged, thus the NaOH in outlet is = 0.95 * 976 = 927.2 kg

The volume of NaOH in outlet after time is = 927.2/1220 = 0.76 m³

The time required to purge the 95% of the NaOH is = 0.76/2 = 0.38 h

4 0
3 years ago
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