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2 years ago

Calculate the wavelength of 26 GeV electrons. Express your answer using two significant figures. λ = m

Physics

1 answer:

Alenkinab [10]2 years ago

6 0

Answer:

4.78 x 10^-17 m

Explanation:

E = 26 GeV

First convert GeV into J

1 GeV = 1.6 x 10^-10 J

E = 26 x 1.6 x 10^-10 = 41.6 x 10^-10 J

Use the formula for energy

E = h c / λ

Where, h is the Plank's constant and λ be the wavelength and c be the velocity of light.

λ = h c / E

λ = ( 6.63 x 10^-34 x 3 x 10^8) / (41.6 x 10^-10)

λ = 4.78 x 10^-17 m

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The two speakers at S1 and S2 are adjusted so that the observer at O hears an intensity of 6 W/m² when either S1 or S2 is sounde

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Answer:

The minimum frequency is 702.22 Hz

Explanation:

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I1 is the intensity of one speaker on which is 6 $W/m^2$

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v is the speed of sound which is 320 m/s.

f is the frequency of the sound which is to be calculated.

$16=4\times 6 \times cos^2(\pi \frac{1 \times f}{320})\\16/24= cos^2(\pi \frac{1f}{320})\\0.667= cos^2(\pi \frac{f}{320})\\cos(\pi \frac{f}{320})=\pm0.8165\\\pi \frac{f}{320}=\frac{7 \pi}{36}+2k\pi \\ \frac{f}{320}=\frac{7 }{36}+2k \\\\ {f}=320 \times (\frac{7 }{36}+2k )$

where k=0,1,2

for minimum frequency $f_1$ , k=1

${f}=320 \times (\frac{7 }{36}+2 \times 1 )\\\\{f}=320 \times (\frac{79 }{36} )\\\\ f=702.22 Hz$

So the minimum frequency is 702.22 Hz

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