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3 years ago

9

The temperature of a 50 g sample of aluminum is raised from 20°c to 60°c when 440 cal of heat are added. the specific heat capac

ity of the aluminum is

1 answer:

GaryK [48]3 years ago

4 0

40 percent is how much aluminum is added

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_____ motion occurs when tectonic plates move apart from each other. A. Divergent B. Transform C. Convergent

Likurg_2 [28]

A. Divergent (pretty sure)

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3 years ago

Read 2 more answers

A particle with charge − 2.74 × 10 − 6 C −2.74×10−6 C is released at rest in a region of constant, uniform electric field. Assum

s2008m [1.1K]

Answer:

241.7 s

Explanation:

We are given that

Charge of particle= $q=-2.74\times 10^{-6} C$

Kinetic energy of particle= $K_E=6.65\times 10^{-10} J$

Initial time= $t_1=6.36 s$

Final potential difference= $V_2=0.351 V$

We have to find the time t after that the particle is released and traveled through a potential difference 0.351 V.

We know that

$qV=K.E$

Using the formula

$2.74\times 10^{-6}V_1=6.65\times 10^{-10} J$

$V_1=\frac{6.65\times 10^{-10}}{2.74\times 10^{-6}}=2.43\times 10^{-4} V$

Initial voltage= $V_1=2.43\times 10^{-4} V$

$\frac{\initial\;voltage}{final\;voltage}=(\frac{initial\;time}{final\;time})^2$

Using the formula

$\frac{V_1}{V_2}=(\frac{6.36}{t})^2$

$\frac{2.43\times 10^{-4}}{0.351}=\frac{(6.36)^2}{t^2}$

$t^2=\frac{(6.36)^2\times 0.351}{2.43\times 10^{-4}}$

$t=\sqrt{\frac{(6.36)^2\times 0.351}{2.43\times 10^{-4}}}$

$t=241.7 s$

Hence, after 241.7 s the particle is released has it traveled through a potential difference of 0.351 V.

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3 years ago

When dots are printed from a laser printer to form letters, they must be close enough so that you do not see the individual dots

balandron [24]

Answer: separate them

Explanation:

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4 years ago

Which of the following is not true regarding atmospheric pressure

Whitepunk [10]

what are the answer choices?

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3 years ago

A long wave with a period of about 15 minutes will travel across the oceans at a speed of approximately _______.

Temka [501]

The speed of the wave is mathematically given as

v=2266.66m/s

A long wave with a period of about 15 minutes will travel across the oceans at a speed of approximately v=2266.66m/s

<h3>Speed of the wave</h3>

Question Parameters:

A long wave with a period of about 15 minutes

Generally the equation for the Wave velocity is mathematically given as

v=\lambda * frequency

Where

f=1/t

Therefore

v=\lambda * frequency

v=\lambda * 1/t

Therefore, with wavelenght of the ocean as 34km

v=34*1000*1/15

v=2266.66m/s

For more information on Speed

brainly.com/question/4931057

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2 years ago