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kati45 [8]
3 years ago
5

Write a funny joke or put a cute animal pic i will give 400 more points to best answer

Engineering
2 answers:
Ksju [112]3 years ago
6 0

Answer:

I had more but brainly was like 'NOOOO"

Explanation:

Mila [183]3 years ago
5 0

Answer:

what do u call a toothless bear?

a gummy bear.

Explanation:

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Giving a way to the law enforcement vehicle and a medical emergency vehicle is necessary. If one approaches an emergency vehicle parked along the roadway one should change the lane as the vehicle may not move and the driver may also waste his or her time also one should also slow down his or her speed while approaching the vehicle as most of the emergency vehicle are in rush to reach the hospital so the driver should maintain some distance with the medical emergency vehicle.

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1. You have a Co-Cr alloy with Young's Modulus: 645 MPa, Poisson ratio 0.28, and yield strength 501 MPa for that alloy when used
bazaltina [42]

Answer:

F_x = 100,200 N

x' = 21.321 cm ... Length

y' =0.7825 cm

z' = 1.565 cm

A' = ( 0.783 x 1.565 ) cm  

Explanation:

Given:

- The Modulus of Elasticity E = 645 MPa

- The poisson ratio v = 0.28

- The Yield Strength Y = 501 MPa

- The Length along x-direction x = 12 cm

- The length along y-direction y = 1 cm

- The length along z--direction z = 2 cm

Find:

The maximum tensile load that can be applied in the longitudinal direction of the bar without inducing plastic deformation. b. The length and cross-sectional area of the bar at its tensile elastic limit.

Solution:

- The Tensile forces within the limit of proportionality is given as:

                                   F_i = б_i*A_jk

- A maximum tensile Force F_x along x direction can be given as:

                                   F_x = Y*A_yz

                                   F_x = 501*( 0.01*0.02)*10^6

                                  F_x = 100,200 N

- The corresponding strains in x, y and z direction due to F_x are:

                                    ξ_x = Y / E

                                    ξ_x = 501 / 645 = 0.7767

                                    ξ_y = ξ_z = -v*Y / E

                                    ξ_y = ξ_z = -0.28*501 / 645 = - 0.2175

- The corresponding change in lengths at tensile elastic stress are:

                                    Δx = x*ξ_x = 12*0.7767 = 9.321 cm

                                    Δy = y*ξ_y = - 1*0.2175 = -0.2175 cm

                                    Δz = z*ξ_z = - 2*0.2175 = -0.435 cm

- The final lengths are:

                                    x' = x + Δx = 12 + 9.321 = 21.321 cm

                                    y' = y + Δy = 1 - 0.2175 = 0.7825 cm

                                    z' = z + Δz = 2 - 0.435 = 1.565 cm

                                       

3 0
4 years ago
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