Complete Question
Suppose you have three identical metal spheres, A, B, and C. Initially sphere A carries a charge q and the others are uncharged. Sphere A is brought in contact with sphere B, and then the two are separated. Spheres CC and BB are then brought in contact and separated. Finally spheres AA and CC are brought in contact and then separated. What is the final charge on the sphere B, in terms of q?
a. 3/8q
b. 1/4q
c. 3/4q
d. q
e. 5/8q
f. 1/3q
g.1/2q
h. 0
Answer:
The correct option is b
Explanation:
From the question we are told that
The charge carried by A is q C
The charge carried by B is 0 C
The charge carried by C is 0 C
When A and B are brought close and then separated the charge carried by A and B is mathematically evaluated as
When C and B are brought close and then separated the charge carried by C and B is mathematically evaluated as
When C and A are brought close and then separated the charge carried by C and A is mathematically evaluated as
Looking at these calculation we can see that the charge carried by B is
To solve this problem, we must take two important steps. First we will convert all the given units, to international system. Later we will define the torque, which is given as the product between the radius of application of the force and the Force acting on the body. Mathematically the latter is,
Here,
r = Radius
F = Force
Now the units,
Replacing,
Therefore the torque that the muscle produces on the wrist is
Answer:
charge C = greatest net force
charge B = the smallest net force
ratio = 9 : 1
Explanation:
we know that in Electrostatic Forces, when 2 charges are at same sign then they repel each other and if they are different signed charges then they attract each other
so as per Coulomb's formula of Electrostatic Forces
F = .....................1
and here k is 9 × N.m²/c² and we consider each charge at distance d
so two charge force at A to B is
F1 =
and force between charges at A to C, at 2d distance
F1 = =
force between charges at A to D, 3d distance
F1 = =
so
Charge a It receives force to the left from b and c and to the right from d
so at a will be
F(a) = -F1 - F2 + F3 ....................2
put here value
F(a) =
solve it
F(a) =
F(a) = = 1.13 F1
and
Charge b It receives force to the right from a and d and to the left from c
F(b) = F1 - F1 + F2 ....................3
F(b) =
F(b) = = 0.25 F1
and
Charge c It receives forces to the right from all charges.
F(c) = F2 + F 1 + F 1 ....................4
F(c) =
F(c) = = 2.25 F1
and
Charge d It receives forces to the left from all charges
F(d) = - F3 - F2 -F 1 ....................5
F(d) =
so
F(d) = = 1.36 F1
and
now we get here ratio of the greatest to the smallest net force that is
ratio =
ratio = 9 : 1
The speed of the ball is 101miles/hr.
A mile is a unit of length that is exactly 1,609.344 metres long. Similarly, 5,280 feet or 1,760 yards make up one mile. The mile is an imperial and common US measurement of distance.
We just have to deal with unit conversions.
One mile is 5280 feet, or 1 ft = 0.000189
The speed of the ball in miles per hour is
So, the speed of the ball in miles per hour is 101miles/hr.
Learn more about miles here;
#SPJ4
Answer:
What is the humidity if the dry-bulb is 10℃ and the wet-bulb is 6℃?
<h2><u>33% According to the Graph</u></h2>Hope this helps!