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3 years ago

In Act V, scene ii of Romeo and Juliet, what role does Friar John play in the catastrophe?

Chemistry

1 answer:

Dafna11 [192]3 years ago

3 0

Answer:

I believe its the 4th one. He goes to give Romeo the message but before he is able to, Balthasar tells Romeo that Juliet is dead. Friar John just wasn't there in time.

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What example show the transformation for electrical change to radiant?

zlopas [31]

When you plug in an electrical heater, it turns the electrical energy into radiant energy.

3 0

3 years ago

In acidic solution, the sulfate ion can be used to react with a number of metal ions. One such reaction is SO42−(aq)+Sn2+(aq)→H2

allsm [11]

Answer:

The final balanced equation is :

$SO_4^{2-}(aq)+4H^+(aq)+Sn^{2+}(aq)\rightarrow H_2SO_3(aq)+H_2O(l)+Sn^{4+}(aq)$

Explanation:

$SO_4^{2-}(aq)+Sn^{2+}(aq)\rightarrow H_2SO_3(aq)+Sn^{4+}(aq)$

Balancing in acidic medium:

First we will determine the oxidation and reduction reaction from the givne reaction :

Oxidation:

$Sn^{2+}(aq)\rightarrow Sn^{4+}(aq)$

Balance the charge by adding 2 electrons on product side:

$Sn^{2+}(aq)\rightarrow Sn^{4+}(aq)+2e^-$ ....[1]

Reduction :

$SO_4^{2-}(aq)\rightarrow H_2SO_3(aq)$

Balance O by adding water on required side:

$SO_4^{2-}(aq)\rightarrow H_2SO_3(aq)+H_2O(l)$

Now, balance H by adding $H^+$ on the required side:

$SO_4^{2-}(aq)+4H^+(aq)\rightarrow H_2SO_3(aq)+H_2O(l)$

At last balance the charge by adding electrons on the side where positive charge is more:

$SO_4^{2-}(aq)+4H^+(aq)+2e^-\rightarrow H_2SO_3(aq)+H_2O(l)$ ..[2]

Adding [1] and [2]:

$SO_4^{2-}(aq)+4H^+(aq)+Sn^{2+}(aq)\rightarrow H_2SO_3(aq)+H_2O(l)+Sn^{4+}(aq)$

The final balanced equation is :

$SO_4^{2-}(aq)+4H^+(aq)+Sn^{2+}(aq)\rightarrow H_2SO_3(aq)+H_2O(l)+Sn^{4+}(aq)$

4 0

3 years ago

Name at least 4 other gases in the atmosphere besides oxygen and nitrogen

BartSMP [9]

Argon,Carbon dioxide,Neon,Helium, and Methane

5 0

3 years ago

Read 2 more answers

The element gallium has an atomic weight of 69.7 and consists of two stable isotopes gallium -69 and gallium -71. The isotope ga

BigorU [14]

Answer:

The answer to your question is Gallium-71 = 70.9202 amu

Explanation:

Gallium atomic weight = 69.7

Gallium-69 = 68.9 amu abundance = 60.4%

Gallium-71 = x abundance = 39.6%

To solve this problem just write an equation and solve it for the mass of gallium-71.

Equation

Gallium = Gallium-69(abundance) + Gallium-71(abundance)

Substitution

69.7 = (68.9)(0.604) + Gallium-71(0.396)

69.7 = 41.6156 + Gallium-71(0.396)

Gallium-71(0.396) = 69.7 - 41.6156

Gallium-71(0.396) = 28.0844

Gallium-71 = 28.0844/0.396

Gallium-71 = 70.9202 amu

3 0

3 years ago

Which statement best describes what makes a base weak? A base is weak when it forms few ions in water. A base is weak when only

mina [271]

Answer:

A base is weak when only a little of it is dissolved in water

Explanation:

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3 years ago