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riadik2000 [5.3K]
3 years ago
8

A person hits a 45-g golf ball. The ball comes down on a tree root and bounces

Physics
1 answer:
Verizon [17]3 years ago
5 0

Answer:

Maximum height, h = 10 m          

Explanation:

It is given that,

Mass of golf ball, m = 45 g = 0.045 kg

The ball comes down on a tree root and bounces  straight up with an initial speed of 14.0 m/s.

We need to find the height the ball will rise  after the bounce. It is based on the conservation of energy such that,

\dfrac{1}{2}mv^2=mgh

h is maximum height raised by the ball

h=\dfrac{v^2}{2g}\\\\h=\dfrac{(14)^2}{2\times 9.8}\\\\h=10\ m

So, the ball will raised to a height of 10 meters.

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Review. Consider the deuterium-tritium fusion reaction with the tritium nucleus at rest:
asambeis [7]

Considering the deuterium-tritium fusion reaction with the tritium nucleus at rest: ¹₂H + ¹₃H → ²₄He + ⁰₁n  the electric potential energy (in electron volts) at this distance is 17.58MeV

<h3>How is the electric potential energy of deuterium-tritium fusion reaction calculated?</h3>

The reaction is  ¹₂H + 1₃H → ²₄He + ⁰₁n

Value of Q = (Mass of ¹₂H + Mass of ¹₃H - Mass of ²₄He- Mass of n) x 931 MeV

Mass of ¹₂H = 2.014102

Mass of ¹₃H = 3.016049

Mass of ²₄He = 4.002603

Mass of n = 1.00867

Therefore Value of Q = [2.014102+3.016049−4.002603−1.00867] × 931 MeV

Therefore Value of Q = 0.01887 × 931 MeV

= 17.58MeV

To learn more about  deuterium-tritium fusion reaction, refer

brainly.com/question/9054784

#SPJ4

7 0
1 year ago
A 85-kg astronaut is stranded from his space shuttle. He throws a 1-kg hammer away from the shuttle with a velocity of 17 m/s. H
algol [13]

Answer:

0.2 m/s

Explanation:

given,

mass of astronaut, M = 85 Kg

mass of hammer, m = 1 Kg

velocity of hammer , v =17 m/s

speed of astronaut, v' = ?

initial speed of the astronaut and the hammer be equal to zero = ?

Using conservation of momentum

(M + m) V = M v' + m v

(M + m) x 0 = 85 x v' + 1 x 17

85 v' = -17

  v' = -0.2 m/s

negative sign represent the astronaut is moving in opposite direction of hammer.

Hence, the speed of the astronaut is equal to 0.2 m/s

4 0
3 years ago
Grains of fine california beach sand are approximately spheres with an average radius of 50 μm and are made of silicon dioxide,
kykrilka [37]

The average radius(r) of each grain is r = 50 nanometers = 50*10^-6 meters

Since it is spherical, so

 Volume=(4/3)*pi*r^3

V= (4/3)*pi*(50*10^-6)^3

V=5.23599*10^-13 m^3

 

We are given the Density(ρ) =2600kg/m^3

 

We know that:

Density(p) = mass(m)/volume(V)

m = ρV

 

So the mass of a single grain is:

m = 5.23599*10^-13 * 2600 = 1.361357*10^-9 kg

 

 

The surface area of a grain is:

a = 4*pi*r^2

a = 4*pi*(50*10^-6)^2

a = 3.14*10^-8 m^2

 

 

Since we know the surface area and mass of a grain, the conversion factor is:

1.361357*10^-9 kg / 3.14*10^-8 m^2

 

Find the Surface area of the cube:

cube = 6a^2

cube = 6*1.1^2  = 7.26m^2

 

multiply this by the converions ratio to get:

total mass of sand grains = (7.26 m^2 * 1.361357*10^-9 kg) / (3.14*10^-8 m^2)

total mass of sand grains = 0.3148 kg = 314.80 g

3 0
3 years ago
♡ GuYs diG cRaZy cHiCks ♡ IvE naMeD my aLtEr Ego AJ
Sonja [21]

Answer:

cooooooooooooooollllllllll

Explanation:

8 0
2 years ago
A bicycle pump contains 20 cm3 of air at a pressure of 100 kPa. The air is then pumped in a tyre of volume 100 cm3. Calculate th
Natasha2012 [34]

Answer:

The pressure of the air in the tyre is 20 kPa

Explanation:

The parameters for the bicycle pump and tyre are;

The volume of air contained in the bicycle pump, V₁ = 20 cm³

The pressure of the air contained in the bicycle pump, P₁ = 100 kPa

The volume (available) of the tyre, where the air is pumped, V₂ = 100 cm³

Let P₂ represent the pressure in the tyre after the air is pumped

By Boyle's law, we have that at constant temperature, the volume of a given mass of gas is inversely proportional to its pressure;

Mathematically, Boyle's law gives the following equation;

P₁ × V₁ = P₂ × V₂

∴ P₂ = (P₁ × V₁)/V₂

Substituting the known values gives;

P₂ = (100 kPa × 20 cm³)/(100 cm³)

∴ P₂ = 100 kPa × 1/5 = 20 kPa

P₂ = 20 kPa

The pressure of the air in the tyre = P₂ = 20 kPa.

7 0
3 years ago
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