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Ilia_Sergeevich [38]
3 years ago
11

Drag the tiles to the correct boxes to complete the pairs.

Physics
1 answer:
Dimas [21]3 years ago
5 0
Brown dwarf is the first box
White dwarf is the second box
Black dwarf is the third box
Red giant is the fourth box
And
Black hole is the last box
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Help me its physical science and i don't know what to do tyyy​
miskamm [114]

The thing to do here is to balance the eqns that is to balance the stoichometric ratios or coefficients of the cpds.

hope you understand. all the best.

7 0
3 years ago
Why are the layers of the earth in the order that they are in?
REY [17]

Answer:

Each layer has its own properties, composition, and characteristics that affects many of the key processes of our planet. They are, in order from the exterior to the interior – the crust, the mantle, the outer core, and the inner core.

Explanation:

3 0
3 years ago
Read 2 more answers
John(body mass=160pounds) is taking off for a long jump. The average ground reaction force Fg at takeoff is 1400 N pointing forw
slega [8]

Answer:

The free body diagram of John is shown in the attached figure (in the FBD john's mass is supposed to be concentrated at his center of mass and FBD is made of center of mass)

b) As shown in the FBD the ground reaction forces are:

i) In X direction F_{x}=1400cos(35^{o})=1146.81N

ii) In Y direction F_{y}=1400sin(35^{o})=803.0N

c) The respective accelerations in x and y direction's is calculated by newton's second law as indicated under

\sum F_{x}=ma_{x}\\\\\therefore a_{x}=\frac{\sum F_{x}}{m}=\frac{1146.8N}{72.57kg}=15.80m/s^{2}\\\\\sum F_{y}=ma_{y}\\\\\therefore a_{y}=\frac{\sum F_{y}}{m}=\frac{803.00-72.57\times 9.81}{72.57}=1.255m/s^{2}

4 0
3 years ago
One evolutionary strategy that has maximized gas diffusion is
Akimi4 [234]

Answer:

Increasing its surface area

Explanation:

In Science, increasing the surface area of a gas increases its collision rate and is one evolutionary strategy that has maximized gas diffusion by catalysing the rate of gaseous reaction.

7 0
3 years ago
A 6.4-N force pulls horizontally on a 1.5-kg block that slides on a smooth horizontal surface. This block is connected by a hori
Elena L [17]

-- Although it's not explicitly stated in the question,we have to assume that
the surface is frictionless.  I guess that's what "smooth" means.

-- The total mass of both blocks is (1.5 + 0.93) = 2.43 kg. Since they're
connected to each other (by the string), 2.43 kg is the mass you're pulling.

-- Your force is 6.4 N.
                                    Acceleration = (force)/(mass) = 6.4/2.43 m/s²<em>
                                                                 </em>
That's about  <em>2.634 m/s²</em>  <em>

</em>
(I'm going to keep the fraction form handy, because the acceleration has to be
used for the next part of the question, so we'll need it as accurate as possible.)

-- Both blocks accelerate at the same rate. So the force on the rear block (m₂) is

       Force = (mass) x (acceleration) = (0.93) x (6.4/2.43) = <em>2.45 N</em>.

That's the force that's accelerating the little block, so that must be the tension
in the string.


7 0
3 years ago
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