Beef and cheddar I believe!!!
Answer:
32.7 grams of Zn will remained in the crucible after cooling.
Explanation:
..[1]
..[2]
Adding [1] + 2 × [2] we get:
..[3]
Moles of ZnS in crucible = 0.50 mol
According to reaction [3]. 2 moles of ZnS gives 2 moles of Zn.
Then 0.50 moles of ZnS will give:
of Zn.
Mass of 0.50 moles of Zn =
= 0.50 mol × 65.4 g/mol =32.7 g
32.7 grams of Zn will remained in the crucible after cooling.
10,000J will raise the temperature of 1 liter of water by 2.38 °C
Using Q = mcΔT where Q = quantity of heat supplied = 10000 J,
m = mass of 1 liter of water = ρV where ρ = density of water = 1000 kg/m³ and V = volume of water = 1 liter = 1 dm³ = 1 × 10⁻³ m³.
So, m = ρV = 1000 kg/m³ × 1 × 10⁻³ m³ = 1 kg,
c = specific heat capacity of water = 4200 J/kg°C and ΔT = temperature change.
Making ΔT subject of the formula, we have
ΔT = Q/mc
Substituting the values of the variables into the equation, we have
ΔT = Q/mc
ΔT = 10000 J/(1 kg × 4200 J/kg°C)
ΔT = 10000 J/(4200 J/°C)
ΔT = 2.38 °C
So, 10,000J will raise the temperature of 1 liter of water by 2.38 °C
Learn more about temperature change here:
brainly.com/question/16384350
Answer:
a. 52.8
Explanation:
To find the number of moles of HCl we use the relation M₁V₁=M₂V₂
where M₁ is the initial molarity, M₂ the new molarity, V₁ the initial volume used, and V₂ the final volume obtained.
M₁=7.91 M
M₂=2.13 M
V₁=?
V₂=196.1 mL
Replacing these values in the relationship.
M₁V₁=M₂V₂
7.91 M× V₁=2.13 M×196.1 mL
V₁=(2.13 M×196.1 mL)/7.91 M
=52.8 mL