Explanation:
Hybridization of O in 
So, water molecule has four hybrid orbitals.
Two hybrid orbitals form 2 sigma bond with two H atoms.
Remaining two hybrid orbitals are occupied by two lone pairs.
Because of lone pair-lone pair repulsion, shape of 
becomes bent.
Water molecule is polar because of difference in eletronegativities of O and H.
O is more electronegative as comapared to hydrogen. So bonding electrons get attracted towards O atom which results in the development of partial negative charge on O atom and partial positive charge on H atoms.
Because of development of partial negative and partial positive charge, water molecule becomes polar.
Answer:
Here's what I get.
Explanation:
Ba is element 56. Its electron configuration is
1s² 2s²2p⁶ 3s²3p⁶ 4s²3d¹⁰4p⁶ 5s²4d¹⁰5p⁶ 6s²
That's a lot of writing.
To lessen the work, chemists have developed the noble gas notation.
The core electrons of Ba (listed in boldface) have the same electron configuration as Xe, the noble gas found two atoms earlier in the Periodic Table.
Chemists replace the core electron configuration with the symbol of the corresponding noble gas.
The noble gas notation for Ba becomes
Ba: [Xe]6s².
What is the question exactly?
Answer:
Dinitrogen tetroxide, commonly referred to as nitrogen tetroxide (NTO), and occasionally (usually among ex-USSR/Russia rocket engineers) as amyl, is the chemical compound N2O4.
Plane is the right answer I thinkkkkk
