1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
valina [46]
3 years ago
11

How many moles of potassium bromide are in 68.5 mL of a 1.65 M solution?Answer is 0.11

Chemistry
1 answer:
fiasKO [112]3 years ago
5 0

Answer:

Number of moles = 0.116 mol

Explanation:

Given data:

Number of moles of potassium bromide = ?

Volume of solution = 68.5 mL

Molarity of solution = 1.65 M

Solution:

First of all we will convert the mL into L.

68.5 mL × 1 L /1000 mL

0.07 L

Molarity = Number of moles / Volume in litter

we will rearrange the formula:

Number of moles = molarity × volume in litter

Now we will put the values in formula:

Number of moles = 1.65 M  ×0.07 L

Number of moles = 0.116 mol

You might be interested in
The skeletal structure of Arachidonic acid, an essential fatty acid, is provided below. Arachidonic acid is best classified as:
Alexandra [31]

Skeletal structure is missing, so i have attached it.

Answer:

Option B: Omega 6 fatty acid

Explanation:

Arachidonic Acid is defined as an essential and unsaturated fatty acid. It's usually found in animal and human fat including the liver, brain, and also glandular organs. While in animals, it is a constituent of their phosphatides.

Arachidonic Acid is formed as a result of the synthesis from dietary linoleic acid and it's a preliminary stage in the biosynthesis of prostaglandins, thromboxanes, and leukotrienes.

In short, Arachidonic acid is basically a long-chain fatty acid which is a C20, Omega 6 polyunsaturated fatty acid that has four Z-double bonds.

4 0
3 years ago
Suppose 50.0g of silver nitrate is reacted with 50g of hydrochloric acid producing silver chloride and a mixture of other produc
docker41 [41]

Answer:

53.6 grams of silver chloride was produced.

Explanation:

AgNO_3+HCl+\rightarrow AgCl+HNO_3

Law of conservation of mass states that mass can neither be created nor be destroyed but it can only be transformed from one form to another form.

This also means that total mass on the reactant side must be equal to the total mass on the product side.

Mass of silver nitrate = 50.0 g

Mass of hydrogen chloride = 50.0 g

Mass of silver chloride = x

Mass of  nitric acid = 46.4 g

Mass of silver nitrate + Mass of hydrogen chloride =

                             Mass of silver chloride + Mass of  nitric acid

[te]50.0 g+50.0 g=x+46.4 g[/tex]

x=50.0 g+50.0 g - 46.4 g = 53.6 g

53.6 grams of silver chloride was produced.

8 0
3 years ago
When is my dad going to get the milk?
Kisachek [45]

Answer:

joe.......

Explanation:

mama......

3 0
3 years ago
Plz help i’m gonna cry i’m in class rn
iragen [17]

Answer:

if ur gonna cry then just dont cry its simple logic guyss!!!!!!!!!!!!

Explanation:

3 0
3 years ago
Pls help 2-3 tyvm ‏‏‎ ‎ ‏‏‎ ‎ ‏‏‎ ‎ ‏‏‎ ‎ ‏‏‎ ‎ ‏‏‎ ‎ ‏‏‎ ‎ ‏‏‎ ‎ ‏‏‎ ‎ ‏‏‎ ‎ ‏‏‎ ‎ ‏‏‎ ‎
Triss [41]

Answer:

I could I guess?

But like only 1 lol

Explanation:

6 0
3 years ago
Other questions:
  • (✓2÷✓3)^5 *(6÷7)^2 simplify
    15·1 answer
  • The answers to number 2-13
    5·1 answer
  • Part A
    8·1 answer
  • The _____ rate is the number of particles that react in a given time to form products.
    7·2 answers
  • Determine the point groups for a. Ethane (staggered conformation) b. Ethane (eclipsed conformation) c. Chloroethane (staggered c
    8·1 answer
  • Identify find a functional groups as indicated
    5·1 answer
  • Please help me thanks​
    9·2 answers
  • Identifying organic compounds
    9·1 answer
  • Layer F can help scientists to correlate the relative age of another layer. What makes layer F useful for relative dating?
    8·2 answers
  • What is the scientific word used to describe the process of the protein in the eggs changing form?
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!