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3 years ago

Choose the correct answer to complete the sentence. Lenses correct vision by__________.

1 answer:

5 0

The best and most correct answer among the choices provided by your question is the second choice or letter B. Lenses correct vision by bending light so that it focuses on the retina
If you are farsighted, your eye does not have adequate focusing power — light rays fail to form a focus point by the time they reach the retina. Contact lenses and glasses correct farsightedness by converging light rays, which increases the eye's focusing power.


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A proton accelerates from rest in a uniform electric field of 595 N/C. At one later moment, its speed is 1.15 Mm/s (nonrelativis

Neko [114]

At one later moment, its speed is 1. 20Mm/s (non relativistic because v is much less than the speed of light).

5 0

3 years ago

A capacitor is charged to a potential difference of 12v it delivers 40% of its stored energy to a lamp what is the final potenti

Korolek [52]

Call the capacitance C.
Note the energy in a capacitor with voltage V is E =½CV². 

Initial energy = ½C(12)² = 72C 

40% of energy is delivered, so 60% remains.in the capacitor. 
Remaining energy = (60/100) x 72C =43.2C 

If the final potential difference is X, the energy stored is ½CX² 
½CX² = 43.2C 
X² = 2 x 43.2 = 86.4 
X = 9.3V

6 0

3 years ago

A small steel wire of diameter 1.0mm is connected to an oscillator and is under a tension of 5.7N . The frequency of the oscilla

kotegsom [21]

Answer:

The power output of the oscillator is 0.350 watt.

Explanation:

Given that,

Diameter = 1.0 mm

Tension = 5.7 N

Frequency = 57.0 Hz

Amplitude = 0.54 cm

We need to calculate the power output of the oscillator

Using formula of the power

$P=\dfrac{1}{2}\times\mu\times\omega^2\times a^2\times v$

Put the value into the formula

$P=\dfrac{1}{2}\times A\times\rho\times\omega^2\times a^2\times\dfrac{\sqrt{T}}{\mu}$

$P=\dfrac{1}{2}\times3.14\times(0.0005)^2\times7850\times(2\times\pi\times57.0)^2\times(0.54\times10^{-2})^2\times\sqrt{\dfrac{5.7}{3.14\times(0.0005)^2\times7850}}$

$P=0.350\ Watt$

Hence, The power output of the oscillator is 0.350 watt.

3 0

3 years ago

A student applies a force 6 newtons to move a bool 1.5 meters across a table. How much work, in joules did the student do?

Anna [14]

Answer:

Explanation:

The work done by an object can be found by using the formula

workdone = force × distance

From the question we have

workdone = 6 × 1.5

We have the final answer as

Hope this helps you

6 0

3 years ago

A gymnast of mass 70.0 kg hangs from a vertical rope attached to the ceiling. You can ignore the weight of the rope and assume t

DiKsa [7]

Answer:

T = 686.7N

Explanation:

For this exercise we will use Newton's second law in this case there is no acceleration,

∑ F = ma

T -W = 0

The gymnast's weight is

W = mg

We clear and calculate the tension

T = mg

T = 70 9.81

T = 686.7N

3 0

3 years ago