Answer:
Speed of both blocks after collision is 2 m/s
Explanation:
It is given that,
Mass of both blocks, m₁ = m₂ = 1 kg
Velocity of first block, u₁ = 3 m/s
Velocity of other block, u₂ = 1 m/s
Since, both blocks stick after collision. So, it is a case of inelastic collision. The momentum remains conserved while the kinetic energy energy gets reduced after the collision. Let v is the common velocity of both blocks. Using the conservation of momentum as :
v = 2 m/s
Hence, their speed after collision is 2 m/s.
Answer : 18.22 meters
Explanation:
1 yard. = 0.9144 meters
85.4 yards = 78.08976 meters
1 minute = 60 seconds
5 minutes = 300 seconds
Speed of Anisa = distance / time
Speed of Anisa = 78.08976 meters / 300 seconds
Speed of Anisa = 0.26029 meters / second.
Distance travelled in 70 seconds = speed * 70
Distance travelled in 70 seconds = 0.26029 * 70 = 18.22 meters
Momentum = (mass) x (speed)
Momentum = (70 kg) x (10 m/s)
<em>Momentum = 700 kg-m/s</em>
The banking angle of the curved part of the speedway is determined as 32⁰.
<h3>
Banking angle of the curved road</h3>
The banking angle of the curved part of the speedway is calculated as follows;
V(max) = √(rg tanθ)
where;
- r is radius of the path
- g is acceleration due to gravity
V² = rg tanθ
tanθ = V²/rg
tanθ = (34²)/(190 x 9.8)
tanθ = 0.62
θ = arc tan(0.62)
θ = 31.8
θ ≈ 32⁰
Learn more about banking angle here: brainly.com/question/8169892
#SPJ1
Answer:
Its the sum of the potential energy and the kinetic energy
