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Sophie [7]
3 years ago
7

If the work done on an object doubles its kinetic energy how is the speed of the object

Physics
1 answer:
damaskus [11]3 years ago
7 0
Gotta be more specific
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Which statement is correct?
miv72 [106K]
'A' is correct. B, C, and D are false statements.
5 0
3 years ago
Read 2 more answers
If a force of 12 N is applied to an object
Varvara68 [4.7K]

Answer:

<h3>The answer is 3 kg</h3>

Explanation:

The mass of the object can be found by using the formula

m =  \frac{f}{a}  \\

f is the force

a is the acceleration

From the question we have

m =  \frac{12}{4}  \\

We have the final answer as

<h3>3 kg</h3>

Hope this helps you

6 0
3 years ago
An atom has a mass of 24 and a nuclear charge of 12. Which statement about the atom is accurate?
Oksana_A [137]

The correct answer is It has equal numbers of neutrons and protons.

A characteristic that can be physically determined, the atomic mass of an atom is equal to the total mass of the protons, neutrons, and electrons that make up the atom. The number of protons in the atom's nucleus is indicated by the atomic number. It is equal to the atomic number in value. Moving over the periodic table causes the nuclear charge to grow. The charge is filled when the electrons approach the protons.

The protons and neutrons of an atom are added to determine the mass number. Therefore, the mass number for each atom will be twice the atomic number (number of protons) if the number of protons (atomic number) and neutrons are identical.

To learn more about  protons and neutrons refer the link:

brainly.com/question/13119648

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5 0
1 year ago
The flywheel of a steam engine runs with a constant angular velocity of 190 rev/min. When steam is shut off, the friction of the
Ivanshal [37]

Answer:

(a) \alpha = - 1.32\ rev/m^{2}

(b) \theta = 13674\ rev

(c) \alpha_{tan} = 8.75\times 10^{- 4}\ m/s^{2}

(d) a = 22.458\ m/s^{2}

Solution:

As per the question:

Angular velocity, \omega = 190\ rev/min

Time taken by the wheel to stop, t = 2.4 h = 2.4\times 60 = 144\ min

Distance from the axis, R = 38 cm = 0.38 m

Now,

(a) To calculate the constant angular velocity, suing Kinematic eqn for rotational motion:

\omega' = \omega + \alpha t

omega' = final angular velocity

\omega = initial angular velocity

\alpha = angular acceleration

Now,

0 = 190 + \alpha \times 144

\alpha = - 1.32\ rev/m^{2}

Now,

(b) The no. of revolutions is given by:

\omega'^{2} = \omega^{2} + 2\alpha \theta

0 = 190^{2} + 2\times (- 1.32) \theta

\theta = 13674\ rev

(c) Tangential component does not depend on instantaneous angular velocity but depends on radius and angular acceleration:

\alpha_{tan} = 0.38\times 1.32\times \frac{2\pi}{3600} = 8.75\times 10^{- 4}\ m/s^{2}

(d) The radial acceleration is given by:

\alpha_{R} = R\omega^{2} = 0.32(80\times \frac{2\pi}{60})^{2} = 22.45\ rad/s

Linear acceleration is given by:

a = \sqrt{\alpha_{R}^{2} + \alpha_{tan}^{2}}

a = \sqrt{22.45^{2} + (8.75\times 10^{- 4})^{2}} = 22.458\ m/s^{2}

5 0
2 years ago
A solid steel column is 4.0 m long and 0.20 m in diameter. Young's modulus for this steel is 2.0 × 1011 N/m2. By what distance d
zzz [600]

Answer:

3.12 x 10^-5 m

Explanation:

Length of steel column, L = 4 m

diameter, d = 0.2 m

radius = half of diameter = 0.1 m

Young's modulus, Y = 2 x 10^11 N/m^2

Mass of truck, m = 5000 kg

Force, F = mass of truck x acceleration due to gravity

F = 5000 x 9.8 = 49000 N

Area of crossection of cable,

A =  \pi r^{2}=3.14\times\0.1\times0.1=0.0314m^{2}

Let ΔL be the shrink in length of cable, then by the formula of Young's modulus

Y=\frac{F\times L}{A\times\Delta L}

\Delta L = \frac{F\times L}{A\times Y}

\Delta L = \frac{49000\times 4}{0.0314\times 2\times10^{11}}

ΔL = 3.12 x 10^-5 m

Thus, the shrink in the length of cable is 3.12 x 10^-5 m.

8 0
3 years ago
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