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N76 [4]
3 years ago
15

In uncompetitive inhibition, the inhibitor can bind to the enzyme only after the substrate binds first. (T/F)

Chemistry
1 answer:
Veronika [31]3 years ago
4 0

Answer:

True

Explanation:

In an uncompetitive inhibition, initially the substrate [S] binds to the active site of the enzyme [E] and forms an enzyme-substrate activated complex [ES].

The inhibitor molecule then binds to the enzyme- substrate complex [ES], resulting in the formation of [ESI] complex, thereby inhibiting the reaction.

This inhibition is called uncompetitive because the inhibitor does not compete with the substrate to bind on the active site of the enzyme.

Therefore, in an uncompetitive inhibition, the inhibitor molecule can not bind on the active site of the enzyme directly. The inhibitor can only bind to the enzyme-substrate complex formed.

       

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How many molecules of copper sulfate are needed to produce 5.0×1024 molecules of sodium sulfate?
lubasha [3.4K]

Answer:

5.0 × 10²⁴ molecules

Explanation:

Step 1: Write the balanced double displacement reaction

2 NaOH + CuSO₄ ⇒ Na₂SO₄ + Cu(OH)₂

Step 2: Calculate the moles corresponding to 5.0 × 10²⁴ molecules of Na₂SO₄

We will use Avogadro's number: there are 6.02 × 10²³ molecules in 1 mole of molecules.

5.0 × 10²⁴ molecule × 1 mol/6.02 × 10²³ molecule = 8.3 mol

Step 3: Calculate the moles of CuSO₄ required to produce 8.3 moles of Na₂SO₄

The molar ratio of CuSO₄ to Na₂SO₄ is 1:1. The moles of CuSO₄ required are 1/1 × 8.3 mol = 8.3 mol.

Step 4: Calculate the molecules corresponding to 8.3 moles of CuSO₄

We will use Avogadro's number.

8.3 mol × 6.02 × 10²³ molecule/1 mol = 5.0 × 10²⁴ molecule

4 0
3 years ago
What is the volume in liters of 321 g of a liquid with a density of 0.84 g/mL?
garri49 [273]
If we have 321 grams of a liquid, and the density is 0.84 g/mL, then we can easily find the volume of the liquid. We just need to take this 0.84 and multiply that by the number of grams. If we do 321 * 0.84, we get 269.64 mL. This is the volume that this liquid has.Remember this equation for future problems: V = D*M. V meaning volume, D meaning density, and M meaning mass. I hope this helps.
7 0
3 years ago
Read 2 more answers
A Geographic Information System is a system of which of these? A. Globes and maps B. Satellites C. Satellite signals and receive
AleksAgata [21]

Answer:

its D

Explanation:

the answer is D

7 0
4 years ago
If an atom of Bromine (Br) becomes an ion, which of the following does it most likely form?
lawyer [7]

Answer:

An atom of Bromine (Br) forms an ion and becomes Br⁻

Explanation:

  • Atoms of elements gain or lose electron(s) to attain a stable configuration and form ions.
  • When an atom gains electron(s) it forms a negatively charged ion called an anion.
  • For example, Bromine is a halogen and its atom requires to gain one electron to attain stability and form a bromine ion (Br⁻).
  • When an atom loses electron(s) it forms a positively charged ion called a cation.
  • For instance, atoms of calcium(Ca) requires to lose two electrons to attain stability and form calcium ion (Ca²⁺).

5 0
3 years ago
How many moles of oxygen will be produced from the decomposition of 3 moles of KClO3?
AlexFokin [52]

Answer:

4.5moles

Explanation:

First, let us balance the equation given from the question. This is illustrated below:

KClO3 —> KCl + O2

There are 2 atoms of O on the right side and 3 atoms on the left. It can be balance by putting 2 in front of KClO3 and 3 in of O2 as shown below

2KClO3 —> KCl + 3O2

Now, we have 2 atoms each of K and Cl on the left side and 1atom each of K and Cl on the right. It can be balance by putting 2 in front of KCl as shown below:

2KClO3 —> 2KCl + 3O2

Now the equation is balanced.

From the balanced equation,

2 moles of KClO3 produced 3 moles of O2.

Therefore, 3 moles of KClO3 will produce = (3 x 3) /2 = 4.5moles of O2.

Therefore 3 moles of KClO3 will produce 4.5 moles of O2

5 0
3 years ago
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