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4 years ago

16 Which change results in the formation of different substances?(1) burning of propane

Chemistry

2 answers:

Fofino [41]4 years ago

8 0

Answer:The correct answer is option (1).

Explanation:

Burning of propane in the presence of oxygen will form carbon-dioxide, water and heat.The chemical reaction can represented as in chemical equation:

$C_3H_8+5O_2\rightarrow 3CO_2+4H_2O+heat$

This is an example of chemical change where new product is formed.

Where as in melting of sold sodium chloride, deposition of carbon-dioxide gas and solidification of water ;phase of the substance is changing that is a physical change is taking place.

Hence, the correct option is (1).

Trava [24]4 years ago

6 0

1. The burning of propane creates different substances: propane and oxygen combine to create water and carbon dioxide:

C3H8 + 5 O2 becomes 3 CO2 + 4 H2O + heat

2. When NaCl melts, it is changing state, but it is still the same NaCl.

3. When gaseous CO2 deposits it is changing state, but it is still the same CO2.

4. When (presumably liquid) water solidifies, it is changing state, but it is still the same water.

So the answer is 1.

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How to make 0.01 Molar solution in 30 ml of water

Leviafan [203]

Answer:

You see the concentration decreased ten fold, from 1 M to 0.1 M.

You can simply increase the volume by ten times.

For example

If you have 250 mL of 1 molar HCl, you can add distilled water upto 2500 mL. Now the concentration is 0.1 molar.

If you want to use the serial dilution method, you can use the C1V1=C2V2 equation.

C1 = starting concentration.

C2 = final concentration.

V is for volume.

So let's say you have 500 mL of 1 M HCl and you only want 50 mL of 0.1 M HCl.

1 M x V1 = 0.1 M x 50 mL

V1 = 5 mL

So you take 5 mL of the original (stock) solution and dilute it up to 50 mL. Then you have 50 mL of 0.1 M HCl.

Explanation:

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3 years ago

After air enter the body through the nose or mouth it then goes to the what?

spin [16.1K]

Answer:

your lungs

Explanation:

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3 years ago

Predict the ground-state electron configuration of the following ions. Write the answer in abbreviated form beginning with noble

Tanzania [10]

Answer: The ground-state electronic configuration of

1) $Ru^{2+}=[Kr]4d^6$

2) $W^{3+]=4f^{14}5d^3$

Explanation: The electronic configuration of elements is defined as the distribution of electrons around the nucleus of that element. It depends on the atomic number of the element.

Atomic number of the element = Number of electrons.

For Ru-element

Atomic number = 44

Number of electrons = 44

Electronic configuration of Ru-element = $[Kr]4d^75s^1$

To form $Ru^{2+}$ , 2 electrons are released from the neutral Ru-element.

So, the electronic configuration of $Ru^{2+}=[Kr]4d^6$

For W-element

Atomic number = 74

Number of electrons = 74

Electronic configuration of W-element = $[Xe]4f^{14}5d^46s^2$

To form $W^{3+}$ , 3 electrons are released from the neutral W-element.

So, the electronic configuration of $W^{3+}=[Xe]4f^{14}5d^3$

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4 years ago

Read 2 more answers

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ivanzaharov [21]

It is the independent variable because you can ‘manipulate’ or ‘change’ it.

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