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sergij07 [2.7K]
3 years ago
8

16 Which change results in the formation of different substances?(1) burning of propane

Chemistry
2 answers:
Fofino [41]3 years ago
8 0

Answer:The correct answer is option (1).

Explanation:

Burning of propane in the presence of oxygen will form carbon-dioxide, water and heat.The chemical reaction can represented as in chemical equation:

C_3H_8+5O_2\rightarrow 3CO_2+4H_2O+heat

This is an example of chemical change where new product is formed.

Where as in melting of sold sodium chloride, deposition of carbon-dioxide gas and solidification of water ;phase of the substance is changing that is a physical change is taking place.

Hence, the correct option is (1).

Trava [24]3 years ago
6 0
1. The burning of propane creates different substances: propane and oxygen combine to create water and carbon dioxide:

<span><span>C<span>3</span>H<span>8</span></span> + 5 <span>O<span>2</span></span> becomes 3 CO2 + 4 <span>H<span>2</span>O</span> + heat
</span><span>
2. When NaCl melts, it is changing state, but it is still the same NaCl.

3. When gaseous CO2 deposits it is changing state, but it is still the same CO2.

4. When (presumably liquid) water solidifies, it is changing state, but it is still the same water.

So the answer is 1.</span>
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Explanation:

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<h2>C</h2>

Explanation:

The atomic number of S is 16

So,number of electrons in S is 16

The electronic configuration of S is 2,8,6

The orbital electronic configuration of S is ^{1}s_{2}^\text{ }^{2}s_{2}^\text{ }^{2}p_{x2}^\text{ }^{2}p_{y2}^\text{ }^{2}p_{z2}^\text{ }^{3}s_{2}^\text{ }^{3}p_{x2}^\text{ }^{3}p_{y1}^\text{ }^{3}p_{z1}^\text{ }

So,the number of orbitals involved is 9.

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3 years ago
An FM radio station broadcasts electromagnetic radiation at a frequency of 103.4 MHz (megahertz; MHz =106s–1). Calculate the w
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Answer:

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The relation between frequency and wavelength is shown below as:

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Given, Frequency = 103.4 MHz = 103.4\times 10^{6}\ Hz  ( as 1 MHz = 10⁶ Hz)

Thus, Wavelength is:

Wavelength=\frac{c}{Frequency}

Wavelength=\frac{2.998\times 10^8}{103.4\times 10^{6}}\ m

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