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Irina18 [472]
3 years ago
14

Consider a galvanic (voltaic) cell that has the generic metals X and Y as electrodes. If X is more reactive than Y (that is, X m

ore readily reacts to form a cation than Y does), classify the following descriptions by whether they apply to the X or Y electrode.A. anodeB.cathodeC. electrons in the wire flow towardD. electrons in the wire flow awayE. cations from salt bridge flow towardF.anions from salt bridge flow towardG.gains massI.loses mass

Chemistry
1 answer:
amm18123 years ago
4 0

Answer:

Here's what I get  

Explanation:

Assume the metals X and Y are immersed in solutions of XNO₃ and YNO₃ and connected by a salt bridge containing KCl.

\begin{array}{lcc}\textbf{Item} & \textbf{Apply to X} & \textbf{Apply to Y}\\\text{A. Anode} & \checkmark & \\\text{B. Cathode} & & \checkmark\\\text{C. Electrons toward} & & \checkmark\\\text{D. Electrons from} &\checkmark & \\\text{E. Cations toward} & & \checkmark \\\text{F. Anions toward} &\checkmark & \\\text{G. Gains mass} & & \checkmark\\\text{H. Loses mass} &\checkmark &\\\end{array}

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Most sulfide compounds of the transition metals are insoluble in water. Many of these metal sulfides have striking and character
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Fe^{2+}(aq)+H_2S(aq)\rightarrow FeS (s)+2H^+ (aq)

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5250 grams or 5.25 kg of carbon monoxide and 375 grams of hydrogen are required to form 6 kg of methanol.

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By stoichiometry of the reaction, the following amounts of moles of each compound participate in the reaction:

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By reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

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mass of carbon monoxide=\frac{6000 grams of methanol*28 grams of carbon monoxide}{32 grams of methanol}

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If by stoichiometry 32 grams of methanol are formed from 2 grams of hydrogen, 6000 grams of methanol are formed from how much mass of hydrogen?

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