The combinations of Strontium and chlorine that are possible are only those in which strontium and chlorine combine in the ratio of 1:2.
1) The possible combinations are
- 4 strontium atoms and 8 chlorine
strontium atoms and
chlorine atoms
2) The combinations that are not possible are
- 20 strontium atoms and 60 chlorine atoms
- 130 billion strontium atoms and 195 billion chlorine
We have to work out the ratio of Strontium and chlorine in each of the given combinations in the question. Only the combinations in which the ratio of Strontium and chlorine is 1:2 is possible.
First case:
4 strontium atoms and 8 chlorine atoms gives a Strontium and chlorine ratio of 1:2 so it is possible.
Second case:
20 strontium atoms and 60 chlorine atoms gives a Strontium and chlorine ratio of 1:3 hence it is not possible.
Third case:
strontium atoms and chlorine atoms gives a Strontium and chlorine ratio of 1:2 hence it is possible.
Fourth case:
130 billion strontium atoms and 195 billion chlorine atoms gives a Strontium and chlorine ratio of 1:1.5 hence it is not possible.
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Answer:
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Explanation:
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Distilled water has the a neutral ph. Pure water always has a ph of 7.
Hi,
Gases are most soluble in water under high pressure and low pressure.
1) We need to convert 12.0 g of H2 into moles of H2, and <span> 74.5 grams of CO into moles of CO
</span><span>Molar mass of H2: M(H2) = 2*1.0= 2.0 g/mol
Molar mass of CO: M(CO) = 12.0 +16.0 = 28.0 g/mol
</span>12.0 g H2 * 1 mol/2.0 g = 6.0 mol H2
74.5 g CO * 1 mol/28.0 g = 2.66 mol CO
<span>2) Now we can use reaction to find out what substance will react completely, and what will be leftover.
CO + 2H2 -------> CH3OH
1 mol 2 mol
given 2.66 mol 6 mol (excess)
How much
we need CO? 3 mol 6 mol
We see that H2 will be leftover, because for 6 moles H2 we need 3 moles CO, but we have only 2.66 mol CO.
So, CO will react completely, and we are going to use CO to find the mass of CH3OH.
3) </span>CO + 2H2 -------> CH3OH
1 mol 1 mol
2.66 mol 2.66 mol
4) We have 2.66 mol CH3OH
Molar mass CH3OH : M(CH3OH) = 12.0 + 4*1.0 + 16.0 = 32.0 g/mol
2.66 mol CH3OH * 32.0 g CH3OH/ 1 mol CH3OH = 85.12 g CH3OH
<span>
Answer is </span>D) 85.12 grams.
