<span>The equation of motion for a rocket in
vertical flight can be obtained from newton’s second law of motion and is
constant-mass system. The equation of motion for a body mass varies with time and mass. When force acts on rocket, the rocket
will accelerate in the direction of force. Therefore, force is equal to the
change in momentum per change in time. For constant mass, force equals mass
times acceleration.</span>
Answer:
b) True. the force of air drag on him is equal to his weight.
Explanation:
Let us propose the solution of the problem in order to analyze the given statements.
The problem must be solved with Newton's second law.
When he jumps off the plane
fr - w = ma
Where the friction force has some form of type.
fr = G v + H v²
Let's replace
(G v + H v²) - mg = m dv / dt
We can see that the friction force increases as the speed increases
At the equilibrium point
fr - w = 0
fr = mg
(G v + H v2) = mg
For low speeds the quadratic depended is not important, so we can reduce the equation to
G v = mg
v = mg / G
This is the terminal speed.
Now let's analyze the claims
a) False is g between the friction force constant
b) True.
c) False. It is equal to the weight
d) False. In the terminal speed the acceleration is zero
e) False. The friction force is equal to the weight
Beginning around 5,500 years ago, the Sumerians built cities along the rivers in Lower Mesopotamia, specialized, cooperated, and made many advances in technology. The wheel, plow, and writing (a system which we call cuneiform) are examples of their achievements.
B . light is <span>the physical energy that stimulates sight</span>
<span>B. a ship slowly sinking</span>
This is not balanced
