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butalik [34]
2 years ago
11

A person on a ferry boat walks from one side of the ferry to the other. Their velocity is 1.5m/s[W] relative to the ferry. The f

erry is travelling at 5.0m/s [S] relative to the shore. Determine the persons velocity to the shore.
Physics
1 answer:
Fittoniya [83]2 years ago
8 0

The person's velocity relative to the shore is determined as 6.5 m/s.

<h3>Velocity of the person</h3>

The velocity of the person is calculated as follows;

V(p/f) = V(p) - V(f)

where;

  • V(p/f) is the velocity of the person relative to the ferry
  • V(p) is the velocity of the person
  • V(f) is velocity of the ferry

1.5 = V(p) - 5

V(p) = 6.5 m/s

Thus, the person's velocity relative to the shore is determined as 6.5 m/s.

Learn more about relative velocity here: brainly.com/question/17228388

#SPJ1

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It depends on "Potential Energy", the amount energy it could have, the amount depending on certain circumstances, like height or force. This was how traditional and some modern rollercoasters work. As the "conveyer belt" pulls you up, the higher you go, the more potential energy you have. Once you are falling down the hill, you are experiencing "Kinetic Energy". Hope it makes sence.
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A line of charge starts at x = +x0 and extends to positive infinity. The linear charge density is λ = λ0x0/x. Determine the elec
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Explanation:

it is given that, the linear charge density of a charge, \lambda=\dfrac{\lambda_ox_o}{x}

Firstly, we can define the electric field for a small element and then integrate for the whole. The very small electric field is given by :

dE=\dfrac{k\ dq}{x^2}..........(1)

The linear charge density is given by :

\lambda=\dfrac{dq}{dx}

dq=\lambda.dx=\dfrac{\lambda_ox_o}{x}dx

Integrating equation (1) from x = x₀ to x = infinity

E=\int\limits^\infty_{x_o} {\dfrac{k\lambda_ox_o}{x^3}}.dx

E=-\dfrac{k\lambda_ox_o}{2}\dfrac{1}{x^2}|_{x_o}^\infty}

E=\dfrac{k\lambda_o}{2x_o}

Hence, this is the required solution.

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Which type of energy is released when a bond between atoms is broken
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Explanation:

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To construct a solenoid, you wrap insulated wire uniformly around a plastic tube 7.1 cm in diameter and 57 cm in length. You wou
ASHA 777 [7]

Answer:

We need about 8769 meters of wire to produce a 2.6 kilogauss magnetic field.

Explanation:

Recall the formula for the magnetic field produced by a solenoid of length L. N turns, and running a current I:

B=\mu_0\,\frac{N}{L} \,I

So, in our case, where B = 2.6 KG = 0.26 Tesla; I is 3 amperes, and L = 0.57 m, we can find what is the number of turns needed;

B=\mu_0\,\frac{N}{L} \,I\\0.26=4\,\pi\,10^{-7}\frac{N}{0.57} \,3\\N=\frac{0.26*0.57\,10^7}{12\,\pi} \\N=39311.27

Therefore we need about 39312 turns of wire. Considering that each turn must have a length of \pi\,D, where D is the diameter of the plastic cylindrical tube, then the total length of the wire must be:

Length=39312\,(\pi\,D)=39312\,(\pi\,0.071)\approx 8768.66\,\,m

We can round it to about 8769 meters.

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3 years ago
A player kicks a soccer ball in a high arc toward the opponent's goal. At the highest point in its trajectory
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At the highest point in its trajectory, the ball's acceleration is zero but its velocity is not zero.

<h3>What's the velocity of the ball at the highest point of the trajectory?</h3>
  • At the highest point, the ball doesn't go more high. So its vertical velocity is zero.
  • However, the ball moves horizontal, so its horizontal component of velocity is non - zero i.e. u×cosθ.
  • u= initial velocity, θ= angle of projection

<h3>What's the acceleration of the ball at the highest point of projectile?</h3>
  • During the whole projectile motion, the earth exerts the gravitational force with a acceleration of gravity along vertical direction.
  • But as there's no acceleration along vertical direction, so the acceleration along vertical direction is zero.

Thus, we can conclude that the acceleration is zero and velocity is non-zero at the highest point projectile motion.

Disclaimer: The question was given incomplete on the portal. Here is the complete question.

Question: Player kicks a soccer ball in a high arc toward the opponent's goal. At the highest point in its trajectory

A- neither the ball's velocity nor its acceleration are zero.

B- the ball's acceleration points upward.

C- the ball's acceleration is zero but its velocity is not zero.

D- the ball's velocity points downward.

Learn more about the projectile motion here:

brainly.com/question/24216590

#SPJ1

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