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Mekhanik [1.2K]
3 years ago
6

HELP! ASAP!

Physics
2 answers:
sp2606 [1]3 years ago
5 0
I believe the answer is 2, Power. :)
mr_godi [17]3 years ago
4 0
The answer is power.
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15. A girl pushes a box that has a mass of 85 kg up an incline. If the giri exerts a force
makvit [3.9K]
<h3><u>Answer;</u></h3>

M.A = 4.25

<h3><u>Explanation;</u></h3>

Mechanical advantage is the ratio of the force required to do something in comparison to the actual force required using a simple machine.

It is the ratio of output force to the input force.

M.A = Output Force/ Input Force

Out put force 85 Kg = 850 N

Input force = 200 N

Therefore;

M.A = 850 N/200 N

        = 4.25

3 0
3 years ago
A circular test track for cars has a circumference of 4.7 km. A car travels around the track from the southernmost point to the
Alika [10]
Well, for the distance traveled, the car goes from the northernmost point to the southernmost point. So, it travels half of the circle's circumference = 4.7/2 = 2.35 km.

For the displacement, by going from the northernmost point to the southernmost point, the car basically just travels the diameter of circle.

So, using the formula: Circumference = 2πr = <span>πd

Hence, the d = C/</span>π = 4.7/<span>π = 1.49605... = 1.5 km (2 significant figures)
Therefore, displacement = 1.5 km</span>
7 0
3 years ago
Where is the fish in reality
vazorg [7]
In reality, the fish are in the ocean.
6 0
3 years ago
Which term describes substances that absorb some wavelenths of light
Y_Kistochka [10]
<span>A pigment is a substance that absorbs some wavelengths of lights and reflects other, giving something its color. Chlorophyll is the green substance that absorbs light and provides energy for photosynthesis.
  
Answer to your question: Pigment
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4 0
3 years ago
The orbital period of a satellite is 2 × 106 s and its total radius is 2.5 × 1012 m. The tangential speed of the satellite, writ
LenaWriter [7]

The orbital period of the satellite[T] is given as 2*10^{6} S.

The radius of the satellite is given [R] 2.5*10^{12} m.

we are asked here to calculate the tangential speed of the satellite.

Before going to get the solution first we have understand the tangential speed.

The tangential speed of a satellite is given as the speed required to keep the satellite along the orbit. If satellite speed is less than tangential speed,there is the chance of it falling down towards earth. If it is more,then it will deviate from it orbit and can't stick to the orbit further.In a simple way  the tangential speed is the linear speed of an object in a circular path.

Now we have to calculate the tangential speed [V].

Mathematically the tangential speed [V]   written as -

                                V=\frac{2\pi R}{T}

where T is the time period of the satellite and R is the radius of the satellite.

                        V=\frac{2*3.14*10^{12} }{2*10^{6} }

                               = 7.85*10^{6} m/s

There is also another way through which we can get  the solution as explained below-

We know that the tangential speed of a satellite V=\sqrt{\frac{GM}{R^{2} } }

where G is the gravitational constant and M is the mas of central object.

But we know that g=\frac{GM}{R^{2} }

                               ⇒GM=gR^{2}  where g is the acceleration due to gravity of that central object.


Hence    V=\sqrt{\frac{gR^{2} }{R} }

               ⇒   V=\sqrt{gR}

By knowing the value of g due to that central object we can also calculate its tangential speed.

                           

 




7 0
3 years ago
Read 2 more answers
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