Answer:
The star is at a distance of 100 parsecs.
Explanation:
The distance can be determined by means of the distance modulus:
(1)
Where M is the absolute magnitude, m is the apparent magnitude and d is the distance in units of parsec.
Therefore, d can be isolated from equation 1
Then, Applying logarithmic properties it is gotten:
(2)
The absolute magnitude is the intrinsic brightness of a star, while the apparent magnitude is the apparent brightness that a star will appear to have as is seen from the Earth.
Since both have the same spectral type is absolute magnitude will be the same.
Finally, equation 2 can be used:
Hence, the star is at a distance of 100 parsecs.
Key term:
Parsec: Parallax of arc seconds
Formula: Ca=Vt^2/r
centripetal acceleration(Ca)= ?
tangential speed(Vt)= 2.8m/s
Radius(r)=2m
Substitute: Ca=2.8^2/2
Ca=3.92m/s^2
Answer:
M_Train>> m_car a_train <a_car
Explanation:
To start the movement of the train or the car, the motorcycle applies a force on the wheels, which starts the acceleration in the case of the train, it has a much greater mass than that of the car, for which to obtain the same acceleration necessary a much greater force
a = F / m
as the mass of the train is greater than that of the car.
a_train <a_car
Something similar happens when the vehicles stop, the engine stops applying force forward and the brakes apply a force backward that creates a negative acceleration that slows down, again as the mass of the train is much greater than the of the car its negative acceleration is much less.
It is good to clarify that to compensate for this the trains have a braking system on all wheels
Answer:
W =23807.68 N
Explanation:
given,
surface area of wing = 19.4 m²
speed over top wing = 67 m/s
speed under wing = 51 m/s
density of air = 1.3 kg/m³
weight of plane
From Bernoulli's principle
where 1 and 2 are two different locations at the same geo potential level
so if we call 1 the lower surface and 2 the upper surface,
we find the pressure differential, P₁ -P₂
then the force acting on the plane is
F=P A
F=1227.2 x 19.4
F =23807.68 N
weight of the plane
W =23807.68 N
Answer:
W = 0
Explanation:
As the satellite moves in a circle the force is perpendicular to the path, therefore the work that is defined by
W = F. r = f r cos θ
Since the force and the radius are perpendicular, the angle θ = 90º and the cosine 90 = 0, therefore there is no work for the circular motion.
W = 0
