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Anastaziya [24]
3 years ago
5

What is the electrical charge of an atom that has lost an electron?

Chemistry
1 answer:
Ket [755]3 years ago
3 0

Sometimes atoms gain or lose electrons. The atom then loses or gains a "negative" charge. These atoms are then called ions. Positive Ion - Occurs when an atom loses an electron (negative charge) it has more protons than electrons.

the answer is NEGATIVE CHARGE

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When a 14.2-g sample of mercury (II) oxide is decomposed into its elements by heating, 13.2 g Hg is obtained. What is the percen
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Mercury (ii) oxide is made up of mercury and oxygen. The total mass of mercury (ii) oxide is 14.2 g, after decomposition 13.2 g of mercury were formed, therefore the mass of oxygen 1 g (14.2 g -13.2 g).
Percentage of oxygen = (1/14.2)×100 = 7.04%
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URGENT!!! What is the concentration in moles per litre of a solution that contains 7.68 g of H2SO4 in 150.0 mL of water?
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@ What is the wavelength of a radio wave having a frequency of 3.75 X 107 Hz?
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6 0
2 years ago
 How much energy is needed to raise the temperature of 125g of water from 25.0oC to 35.0oC?  The specific heat of water is 4.184
Anvisha [2.4K]

Hello!

To find the amount of energy need to raise the temperature of 125 grams of water from 25.0° C to 35.0° C, we will need to use the formula: q = mcΔt.

In this formula, q is the heat absorbed, m is the mass, c is the specific heat, and Δt is the change in temperature, which is found by final temperature minus the initial temperature.

Firstly, we can find the change in temperature. We are given the initial temperature, which is 25.0° C and the final temperature, which is 35.0° C. It is found by subtract the final temperature from the initial temperature.

35.0° C - 25.0° C = 10.0° C

We are also given the specific heat and the grams of water. With that, we can substitute the given values into the equation and multiply.

q = 125 g × 4.184 J/g °C × 10.0° C

q = 523 J/°C × 10.0° C

q = 5230 J

Therefore, it will take 5230 joules (J) to raise the temperature of the water.

6 0
3 years ago
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