Answer:
0.2631 N/C
Explanation:
Given that:
The radius of the wire r = 0.22 mm = 0.22 × 10⁻³ m
The radius of the thick wire r' = 0.55 mm = 0.55 × 10⁻³ m
The numbers of electrons passing through B, N = 6.0 × 10¹⁸ electrons
Electron mobility μ = 6.0 x 10-4 (m/s)/(N/C)
= 0.0006
The number of electron flow per second is calculated as follows:
The magnitude of the electric field is:
E =
E =
E =
E = 0.2631 N/C
It will float because the density is less than 1
Answer:true
Explanation:because the double lights
Answer:
a
The mass is
b
The velocity is
Explanation:
From the question we are told that
The speed of the protons is
The mass of the protons is
The speed of the rebounding protons are
The negative sign shows that it is moving in the opposite direction
Now according to the law of energy conservation mass of one nucleus of the unknown element. is mathematically represented as
Where is the mass of a single proton
So substituting values
The mass of on proton is
So
Now according to the law of linear momentum conservation the speed of the unknown nucleus immediately after such a collision is mathematically evaluated as
Now because before collision the the nucleus was at rest
So
=>
Recall that
So
=>
substituting values
Answer:
I'm pretty sure it'sssss A