Ask question

Ask question

All categories

4 years ago

7

Think about decorative strings of lights that you might see displayed for a holiday. If the lights are on a series circuit, what

will happen if one bulb burns out? What will happen on a parallel circuit if one bulb burns out?

1 answer:

USPshnik [31]4 years ago

7 0

That bulb will break insise

You might be interested in

If you're driving 55 MPH and you suddenly need to stop, how many feet will you travel before the car comes to a stop

lys-0071 [83]

ANSWER: 170 Feet
REASON: with good breaks and a dry road your car should stop and skip 170 feet, with perception and reaction time of stopping you should stop within 170 feet

5 0

3 years ago

A tennis ball is hit with a vertical speed of 10 m/s and a horizontal speed of 30 m/s. How far will the ball travel horizontally

sweet-ann [11.9K]

Answer:

D) 60 m

Explanation:

We can use the constant acceleration equation that contains displacement, initial velocity, acceleration, and time. We want to solve for the time that the ball was in the air first.

Δx = v_i * t + 1/2at²

Let's use this equation in terms of the y-direction.

Δx_y = (v_i)y * t + 1/2a_y * t²

The vertical displacement will be 0 meters since the ball will be on the floor. The initial vertical velocity is 10 m/s, the vertical acceleration is g = 10 m/s², and we are going to solve for time t.

Let's set the upwards direction to be positive and the downwards direction to be negative. We must use -g to be consistent with our other values.

Plug the known values into the equation.

0 m = 10 m/s * t + 1/2(-10 m/s²) * t²

Simplify the equation.

0 = -10t + 5t²
0 = 5t² - 10t

Factor the equation.

0 = 5t(t - 2)

Solve for t by setting both factors to 0.

5t = 0
t - 2 = 0

We get t = 0, t = 2. We must use t = 2 seconds because it is the only value for t that makes sense in the problem.

Now that we have the time that the ball was in the air, we can use the same constant acceleration equation to determine the horizontal displacement of the tennis ball. We will use this equation in terms of the x-direction:

Δx = v_i * t + 1/2at²
Δx_x = (v_i)x * t + 1/2a_x * t²

Plug the known values into the equation.

Δx_x = 30 m/s * 2 sec + 1/2(0 m/s²) * (2 sec)²

We can eliminate the right side of the equation since anything multiplied by 0 outputs 0.

Δx_x = 30 * 2
Δx_x = 60

The horizontal displacement of the ball is 60 meters. Therefore, the answer is D) 60 m.

4 0

3 years ago

If an object has a mass of 1417g and it is moved 47 meters in 90 seconds, how much power was used?

astraxan [27]

Mass of the object is given as

$m = 1417 g = 1.417 kg$

now the speed of object is given as

$v = \frac{d}{t}$

here we know that

$d = 47 m$

$t = 90 s$

now we will have

$v = \frac{47}{90} = 0.52 m/s$

now we will have kinetic energy of the object as

$KE = \frac{1}{2}mv^2$

$KE = \frac{1}{2}(1.417)(0.52)^2$

$KE = 0.19 J$

now the power is defined as rate of energy

so here we can find power as

$P = \frac{KE}{t}$

$P = \frac{0.19}{90} = 2.14\times 10^{-3} W$

so above is the power used for the object

3 0

4 years ago

A spring is hung from the ceiling. When a block is attached to its end, it stretches 2.5 cm before reaching its new equilibrium

Brums [2.3K]

Answer:

0.99Hz

Explanation:

Using F= -mx ( spring force)

At equilibrium the gravitational force will be balanced by the spring force so mg= kx

K= mg/ 0.25 N/m

But

Frequency f= 1/2pi √g/0.25

Frequency is 0.99Hz

6 0

3 years ago

In the Daytona 500 auto race, a Ford Thunderbird and a Mercedes Benz are moving side by side down a straightaway at 71.5 m/s. Th

lisabon 2012 [21]

Answer:

957.4845 m

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration

$v^2-u^2=2as\\\Rightarrow a=\frac{v^2-u^2}{2s}\\\Rightarrow a=\frac{0^2-71.5^2}{2\times 250}\\\Rightarrow a=-10.2245\ m/s^2$

$v=u+at\\\Rightarrow t=\frac{v-u}{a}\\\Rightarrow t=\frac{0-71.5}{-10.2245}\\\Rightarrow t=6.993\ s$

Time taken by the thunderbird to stop is 6.993 seconds

Time the thunderbird was at the pit is 5 seconds

$v^2-u^2=2as\\\Rightarrow a=\frac{v^2-u^2}{2s}\\\Rightarrow a=\frac{71.5^2-0^2}{2\times 350}\\\Rightarrow a=7.3\ m/s^2$

$v=u+at\\\Rightarrow t=\frac{v-u}{a}\\\Rightarrow t=\frac{71.5-0}{7.3}\\\Rightarrow t=9.79\ s$

Time taken to accelerate back to 71.5 m/s is 9.79 seconds

Total time to this point is 6.993+5+9.79 = 21.783 seconds

The Mercedes Benz is moving at a constant velocity hence it has no acceleration and we use the formula

Distance = Speed × Time

⇒Distance = 71.5 × 21.783 = 1557.4845 m

The thunderbird has covered 250+350 = 600 m

So, the distance between them is 1557.4845-600 = 957.4845 m

7 0

3 years ago