Question

A submarine dives 185.0 m at an angle of 15.0◦ below the horizontal. What is the horizontal component of the submarine’s displacement? Use the coordinate system where positive x is to the right and positive y is up. Answer in units of m.

Answer 1

Answer:

Horizontal component, $d_x=178.69\ m$

Explanation:

It is given that,

Displacement of the submarine, d = 185 m

It is at an angle of 15 degrees below the horizontal. We need to find the horizontal component of the submarine's displacement. It is given by :

$d_x=d\ cos\theta$

Substituting the values in above equation as :

$d_x=185\times \ cos(15)$

$d_x=178.69\ m$

So, the horizontal component of the submarine’s displacement is 178.69 meters. Hence, this is the required solution.