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Ymorist [56]
3 years ago
15

How much heat is absorbed by a 75g iron skillet when it’s temperature rises from 5c to 20c?

Physics
1 answer:
alexira [117]3 years ago
6 0

Answer: Q=499.5 J  

Explanation:

The heat (thermal energy) absorbed by the iron skillet can be found using the following equation:

Q=m.C.\Delta T   (1)

Where:

Q is the heat  (absorbed)

m=75 g is the mass of the element (iron in this case)

C is the specific heat capacity of the material. In the case of iron is C=0.444\frac{J}{g\°C}

\Delta T=T_{f}-T_{i}=20\°C - 5\°C= 15\°C is the variation in temperature

Knowing this, lets rewrite (1) with these values:

Q=(75 g)(0.444\frac{J}{g\°C})(15\°C)  (2)

Finally:

Q=499.5 J  

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(a) The magnitude of the electric field at point 5.5m is 2.35 x 10⁴ N/C.

(b) The magnitude of the electric field at point 2.5m is 5.18 x 10⁴ N/C.

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E = \frac{\lambda}{2\pi \varepsilon _0 r} \\\\E = \frac{7.2 \times 10^{-6}}{2\pi \times 8.85 \times 10^{-12} \times 5.5} \\\\E = 2.35 \times 10^4 \ N/C

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E = \frac{\lambda}{2\pi \varepsilon _0 r} \\\\E = \frac{7.2 \times 10^{-6}}{2\pi \times 8.85 \times 10^{-12} \times 2.5} \\\\E = 5.18 \times 10^4 \ N/C

Thus, the magnitude of the electric field at points of 5.5m is 2.35 x 10⁴ N/C, and the magnitude of the electric field at points of 2.5m is 5.18 x 10⁴ N/C.

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Focal length is the distance between the point of convergence of your lens and the sensor or film recording the image.

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