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saveliy_v [14]
3 years ago
13

What is the median of 5 12 7 15 3 6 1

Physics
1 answer:
xxMikexx [17]3 years ago
7 0

Answer:

6

Explanation:

The median is found by listing the numbers in order numerically and finding the one that is right in the middle. In this case you have 1, 3, 5, 6, 7, 12, 15 where the middle term is 6.

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A certain AM radio wave has a frequency of 1.12 x 100 Hz. Given that radio waves travel at
riadik2000 [5.3K]

Answer: 267 m

Explanation:

2.99x10^8 m/s

———————-

1.12 x 10^6 Hz

3 0
3 years ago
Which biome would you not find trees or deep rooted plants in ?
Dafna1 [17]
The tundra because it's growing season is too short.
6 0
3 years ago
Read 2 more answers
What is amplitude, wavelength, and frequency?
krek1111 [17]
Wavelength- <span>distance between successive crests of a wave.

frequency- t</span><span>he rate at which something occurs or is repeated over time.

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6 0
3 years ago
Which of the following are true about a "simple compressible system"? It cannot be a mixture of different substances (e.g. oxyge
fomenos

Explanation:

The volume of a simple compressible system is not fixed. At a state of equilibrium, there should be uniformity in the entire system.

From the question we have here, these are the correct options:

1. It cannot be a mixture of different substances (e.g. oxygen and nitrogent)

2. It can be composed of any phases of a substance: solid, liquid, and/or gas

3. It's state is specified if given two independent, intensive thermodynamic properties.

4 0
3 years ago
A thin-walled cylindrical pressure vessel is subjected to an internal gauge pressure, p=75 psip=75 psi. It had a wall thickness
Mekhanik [1.2K]

To solve this problem we must apply the concept related to the longitudinal effort and the effort of the hoop. The effort of the hoop is given as

\sigma_h = \frac{Pd}{2t}

Here,

P = Pressure

d = Diameter

t = Thickness

At the same time the longitudinal stress is given as,

\sigma_l = \frac{Pd}{4t}

The letters have the same meaning as before.

Then he hoop stress would be,

\sigma_h = \frac{Pd}{2t}

\sigma_h = \frac{75 \times 8}{2\times 0.25}

\sigma_h = 1200psi

And the longitudinal stress would be

\sigma_l = \frac{Pd}{4t}

\sigma_l = \frac{75\times 8}{4\times 0.25}

\sigma_l = 600Psi

The Mohr's circle is attached in a image to find the maximum shear stress, which is given as

\tau_{max} = \frac{\sigma_h}{2}

\tau_{max} = \frac{1200}{2}

\tau_{max} = 600Psi

Therefore the maximum shear stress in the pressure vessel when it is subjected to this pressure is 600Psi

6 0
3 years ago
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