The change in the internal energy of the gas is 1.5×10∧3 J.
The internal energy of an ideal gas is directly proportional to the temperature of the gas:
ΔE = 3/2 × n × R × ΔT
ΔT = 320 K - 260 K
ΔT = 60 K; change of the temperature
n = 2.0 mol: amount of a monatomic ideal gas
R = 8.1 J/mol×K;the ideal gas constant
ΔE = 3/2 × 2 mol × 8.1 J/mol×K × 60 K
ΔE = 1500 J
ΔE = 1.5×10∧3 J; the internal energy of the gas
Isobaric process is a type of process in which the pressure of the system stays constant.
More about an isobaric process: brainly.com/question/28106078
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Answer:
Hello There!!
Explanation:
The answer is B.Year
It takes 365 days for the earth to orbit the sun. 365 days is 1 year.
hope this helps,have a great day!!
~Pinky~
Answer:
33.3 kg of air
Explanation:
This is a problem of conversion unit.
Density is mass / volume
Therefore we have to calculate the volume in the room, to be multiply by density. That answer will be the mass of air.
Volume of the room → 9 ft . 11 ft . 10 ft = 990 ft³
Density is in g/L, therefore we have to convert the ft³ to dm³ (1 dm³ = 1L)
990 ft³ . 28.3 dm³ / 1ft³ = 28017 dm³ → 28017 L
This is the volume of the room, if we replace it in the density formula we can know the mass of air in g.
1.19 g/L = Mass of air / 28017 L
Mass of air = 28017 L . 1.19 g/L → 33340 g of air
Finally, let's convert the mass in g to kg → 33340 g . 1kg / 1000 g = 33.3 kg
Answer:
6.4 L
Explanation:
When all other variables are held constant, you can use Boyle's Law to find the missing volume:
P₁V₁ = P₂V₂
In this equation, "P₁" and "V₁" represent the initial pressure and volume. "P₂" and "V₂" represent the final pressure and volume. You can find the theoretical volume by plugging the given values into the equation and simplifying.
P₁ = 3.2 atm P₂ = 1.0 atm
V₁ = 2.0 L V₂ = ? L
P₁V₁ = P₂V₂ <----- Boyle's Law
(3.2 atm)(2.0 L) = (1.0 atm)V₂ <----- Insert values
6.4 = (1.0 atm)V₂ <----- Simplify left side
6.4 = V₂ <----- Divide both sides by 1.0
The answer will be A & B not only because it makes sense but evaporation is taking water away not adding to (gaining)