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scoray [572]
3 years ago
11

What are 3 reasons why the application of physics is important in the work or school environment?​

Physics
1 answer:
gregori [183]3 years ago
5 0

Answer:

Physics is important in our daily life because it deals with daily objects we need like light, electricty and sound. Without physics, we cant have the ability to see because lights wont be a thing, we cant use phones, cars and such because they wont work without electricty, you wont be able to listen to your favourite band without sound!

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Kinetic Energy Assignment: Lab Report
kompoz [17]

Answer:

so what do we gotta do?

Explanation:

is there any book or homework?

4 0
3 years ago
Anyone help me please?
choli [55]

Answer:

I  believe that its B my apologies  if its wrong/

Explanation:

3 0
3 years ago
A diver jumps up off a pier at an angle of 25° with an initial velocity of 3.2 m/s. How far from the pier will the diver hit the
rjkz [21]

Answer:

0.8 meters.

I just answered this ame question myself on a test I was taking.

6 0
3 years ago
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In the past, how did people use the systematic movement of celestial bodies? Select all that apply.
vredina [299]
The answer is actually a,b, and d
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5 0
3 years ago
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if a person can jump maximum along distance of 3m ,on the earth how far could be jump on the moon where acceleration due to grav
allochka39001 [22]

Answer:

The person can jump 48 m on the Moon

Explanation:

The question parameters are;

The maximum long jump distance of a person on Earth, R_{max} = 3 m

The acceleration due to gravity on the Moon = 1 ÷ 16 of that on Earth

The distance the person can jump on the Moon is given as follows;

A person performing a jump across an horizontal distance on Earth (under gravitational force) follows the path of the motion of a projectile

The horizontal range, R_{max}, of a projectile motion is found by using the following formula

R_{max} = \dfrac{u^2}{g}

Where;

g = The acceleration due to gravity = 9.8 m/s²

Therefore, we have;

R_{max} = 3 \, m = \dfrac{u^2}{9.8 \, m/s^2 }

u² = 3 m × 9.8 m/s² = 29.4 m²/s²

Therefore, on the Moon, we have;

The acceleration due to gravity on the Moon, g_{Moon} = 1/16 × g

∴ g_{Moon} = 1/16 × g = 1/16 × 9.8 m/s² ≈ 0.6125 m/s²

R_{max \ Moon} = \dfrac{u^2}{g_{Moon}}   = \dfrac{29.4 \ m^2/s^2}{0.6125 \, m/s^2 } \approx 48 \, m

The maximum distance the person can jump on the Moon with the same velocity which was used on Earth is R_{max \ Moon} ≈ 48 m

8 0
3 years ago
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