The ball will accelerate at a rate of
Explanation:
We can describe the motion of the ball by using Newton's second law, which states that the net force exerted on an object is equal to the product between the mass of the object and its acceleration:
where
F is the net force
m is the mass
a is the acceleration
In this problem,
F = 14 N is the force exerted on the ball
m = 4.5 kg is the mass of the ball
Solving the equation, we find its acceleration:
So, the ball will accelerate at a rate of .
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The force = 0.3 * 9.8 = 2.94
x = 0.13
k = 2.94/0.13
k = 22.6 N/m
The answer is <span>d. the sun</span>
For question 1 if you have your acceleration equal to -9.8m/s^2 then you can find how fast it is traveling when it hits the water. You would use the equation Vf=Vi+a(t). You are looking for your Vf. Vi is 0m/s. a is -9.8m/s^2. t is 3.87s. If you now plug in what you have and solve you would end up with Vf=-37.926. For how far did it drop use the equation, d=Vi(t)+1/2(a)(t)^2. plug in the Vi, a, and t and solve. Then you are left with the distance vertically being 73.38681m (don't forget sig figs). (When you solve for d it ends up being negative, but because you can't ever go backwards in distance it has to be positive)
Answer:
See the explanation below
Explanation:
Ohm law is defined as the voltage is equal to the current product by the resistance.
V = I * R
where:
V = voltage [volt]
I = current [amp]
R = resistance [ohm]
Therefore for a current to exist there must be a voltage and elements that exert resistance to the passage of electrons from one point to another.
There must be a closed loop between the connection points of the source, so that the current can flow freely. Any opening of the circuit will interrupt the current flow.