Calculate the total heat (joules) of formation for 30 grams of water that is heated from 32C to 48C
1 answer:
Answer:
2008.3 J
Explanation:
Use the equation q=mcΔT where
q = heat
m = mass
c = specific heat capacity (for water this is 4.184 and is a given)
delta T = change in temperature in C (final - initial)
q = 30 g x 4.184 J/g*C x (48-32)
q = 2008.3 J (or 2 kJ)
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