The camcorder uses a current of 1.4 A.
<em>P = VI
</em>
<em>I</em> = <em>P</em>/<em>V</em> = 11 W/8 V = 1.4 A
<em>Note</em>: The answer can have only <em>one significant figure</em> because that is all you gave for the voltage. However, I calculated the current to two significant figures.
E = hf
c = speed of electromagnetic wave, c ≈ 3 * 10⁸ m/s,
Planck's constant h = 6.63 *10⁻³⁴ Js
h = Planck's constnat, Frquency, f = c/λ = (3*10⁸)/(488*10⁻⁹)
E = hf
E = hc/λ
E = (6.63 * 10⁻³⁴ * 3 * 10⁸) /(488 * 10⁻⁹)
Energy, E ≈ 4.0758 * 10⁻¹⁹ Joules.
Uhm I think 5 sorry if I’m wrong
I don’t understand wha u just said but thanks for the points
