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Finger [1]
3 years ago
5

A compound held together by ionic bonds is called a ___?

Chemistry
2 answers:
svetlana [45]3 years ago
5 0

Answer:

Salt

Explanation:

Ionic/electrovalent bond is a type of intramolecular force that involves the transfer of electrons from a metallic atom (to form a cation) to a non-metallic atom (to form a cation). Compounds that have ionic bonds are called ionic compounds/salts. Examples of ionic salts include NaCl, NaF, KI, KBr among others.

In NaCl for instance, the sodium (Na) atom donates the only electron on its outermost shell to form sodium ion (Na⁺) while chlorine (Cl) receives this electron to become chloride ion (Cl⁻).

Arisa [49]3 years ago
4 0
A compound held together by ionic bonds is called a salt
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A lab technician mixed a 550 ml solution of water and alcohol. if​ 3% of the solution is​ alcohol, how many milliliters of alcoh
kupik [55]

The solution 550 ml total and first we will find the amount of alcohol. 3% = 0.03 550 ml x .03 = 16.5 ml alcohol
 Then to find the amount of water used, we just have to subtract the amount of alcohol from the total volume  
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8 0
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A student has a 2.19 L bottle that contains a mixture of O 2 , N 2 , and CO 2 with a total pressure of 5.57 bar at 298 K . She k
Sergeeva-Olga [200]

<u>Answer:</u> The partial pressure of oxygen gas is 2.76 bar

<u>Explanation:</u>

To calculate the number of moles, we use the equation given by ideal gas which follows:

PV=nRT

where,

P = pressure of the gas = 5.57 bar

V = Volume of the gas = 2.19 L

T = Temperature of the gas = 298 K

R = Gas constant = 0.0831\text{ L bar }mol^{-1}K^{-1}

n = Total number of moles = ?

Putting values in above equation, we get:

5.57bar\times 2.19L=n\times 0.0831\text{ L. bar }mol^{-1}K^{-1}\times 298K\\\\n=\frac{5.57\times 2.19}{0.0831\times 298}=0.493mol

To calculate the mole fraction of carbon dioxide, we use the equation given by Raoult's law, which is:

p_{A}=p_T\times \chi_{A}         ........(1)

where,

p_A = partial pressure of carbon dioxide = 0.318 bar

p_T = total pressure = 5.57 bar

\chi_A = mole fraction of carbon dioxide = ?

Putting values in above equation, we get:

0.318bar=5.57bar\times \chi_{CO_2}\\\\\chi_{CO_2}=\frac{0.381}{5.57}=0.0571

  • Mole fraction of a substance is given by:

\chi_A=\frac{n_A}{n_A+n_B}

We are given:

Moles of nitrogen gas = 0.221 moles

Mole fraction of nitrogen gas, \chi_{N_2}=\frac{0.221}{0.493}=0.448

Calculating the partial pressure of oxygen gas by using equation 1, we get:

Mole fraction of oxygen gas = (1 - 0.0571 - 0.448) = 0.4949

Total pressure of the system = 5.57 bar

Putting values in equation 1, we get:

p_{O_2}=5.57bar\times 0.4949\\\\p_{O_2}=2.76bar

Hence, the partial pressure of oxygen gas is 2.76 bar

6 0
3 years ago
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lapo4ka [179]

Answer:

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Explanation:

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Lelechka [254]

Answer:

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