Answer:
The maximum compression distance of the spring is 0.375 m
Explanation:
The given parameters are;
The weight of the elevator and the frog = 4,000.0 N
The location of the elevator above the spring = 5.00 m
The force constant of the spring, k = 8,000.0 N/m
The frictional force of the brakes = 1,000.0 N
The net force, F, of the elevator on the spring is F = 4,000.0 N - 1,000.0 N = 3,000.0 N
F = 3,000.0 N
The maximum compression distance of the spring, x is given as follows;
F = k × x
Substituting the known values gives;
3,000.0 N = 8,000.0 N/m × x
∴ x = (3,000.0 N)/(8,000.0 N/m) = 0.375 m
x = 0.375 m = 37.5 cm
The maximum compression distance of the spring, x = 0.375 m.
