What happens to an acid when it dissolves in water?

Chemistry

2 answers:

shusha [124]3 years ago

5 0

The concentration of the acid decreases

jekas [21]3 years ago

3 0

Answer:

the concentration of the acid decreases

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Which of the following atoms is likely to transfer (and lose) an electron when it forms an ion? Please choose the correct answer

mestny [16]

Answer:

An atom containing 11 electrons

Explanation:

Metal atoms form ions by a loss of electrons whereas non-metal atoms form ions by the gain of electrons.

The group 1 elements or alkali metals form lose their one valence shell electrons when forming ions; Group 2 metals lose two while Group 3 lose three. On the other hand, non-metal atoms found in Group 5, 6, and 7 forms ions by gaining one, two and three electrons respectively.

Using the electronic configuration of atoms, their groups in the Periodic Table can be determined.

An atom containing 6 electrons has the configuration 2,4 and thus belongs to Group 4.

An atom with 2 electrons belongs to Group 2

An atom with 11 electrons has the configuration 2,8,1 and thus belongs to Group 1

An atom with 10 electrons has the configuration 2,8 and thus belongs to Group 8

An atom with 8 electrons has the configuration 2,6 and thus belongs to Group 6.

From the above, it can be seen that an atom containing 11 electrons belongs to Group 1 and will lose an electron to form an ion.

8 0

3 years ago

The production of iron and carbon dioxide from iron(iii) oxide and carbon monoxide is an exothermic reaction. which expression c

NARA [144]

Missing question:
A. [3.40 mol Fe2O3 (s) × 26.3 kJ/1 mol Fe2O3 (s)] / 2
B. 3.40 mol Fe2O3 (s) × 26.3 kJ/1 mol Fe2O3 (s) 
C. 26.3 kJ/1 mol Fe2O3 (s) / 3.40 mol Fe2O3 (s) 
D. 26.3 kJ/1 mol Fe2O3 (s) – 3.40 mol Fe2O3 (s).
Answer is: B.
Chemical reaction: Fe₂O₃(s) + 3CO(g) → 2Fe(s) + 3CO₂(g);ΔH = + 26.3 kJ.
When one mole of iron(III) oxide reacts 26,3 kJ of energy is required and for 3,2 moles of iron(III) oxide 3,2 times more energy is required.

8 0

3 years ago

Read 2 more answers

Draw the product that valine forms when it reacts with excess CH3CH2OH and HCl followed by a wash with aqueous base.

-BARSIC- [3]

Answer:

Product: ethyl L-valinate

Explanation:

If we want to understand what it is the molecule produced we have to analyze the reagents. We have valine an amino acid, in this kind of compounds we have an amine group ( $NH_2$ ) and a carboxylic acid group ( $COOH$ ). Additionally, we have an alcohol ( $CH_3CH_2OH$ ) in the presence of HCl (a strong acid) in the first step, and a base ( $OH^-$ ).

When we have an acid and an alcohol in a vessel we will have an esterification reaction. In other words, an ester is produced. As the first step, the oxygen in the C=O (in the carboxylic acid group) would be protonated. In the second step, the ethanol attacks the carbon in the C=O of the carboxylic acid group producing a new bond between the oxygen in the ethanol and the carbon in the carboxylic acid. In step 3, a proton is transferred to produce a better leaving group ( $H_2O$ ). In step 4, a water molecule leaves the main structure to produce again the double bond C=O. Finally, a base ( $OH^-$ ) removes the hydrogen from the C=O bond to produce ethyl L-valinate