Answer:

Explanation:
given,
charge = -5.0 μC
Electric force, F = 11 i^ N
force would a proton experience = ?
we know



we know charge of proton is equal to 1.6 x 10⁻¹⁹ C
using formula



Force experienced by the photon in the same field is equal to 
Answer:
The answer is c. 11.42 Ohm
Explanation:
The conductor's resistance is calculated by the formula in the figure.
So, you have to replace the given values into the formula.
Resistance of a conductor is equal to the product of rho by the lengh of the conductor divided the cross-sectional area of the conductor.

Scalar Quantity :-
→ These are the quantities with magnitude only . These quantities doesn't have to be mentioned with direction
eg.)=> Mass , Temprature .
Vector Quantity :-
→ These quantities are described with both Magnitude and Direction . These quantities follow special type of algebra called Vector algebra .
eg.)=> Force , Displacement
_______________________________
Hope It Helps You. ☺
Answer : The significant digit is 6
Explanation :
Multiply
by 
Now, on multiplying


Now, the significant digit is 6.
Hence, this is the required solution.