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finlep [7]
3 years ago
13

What are 3 ways a car can accelerate? (CRE)

Physics
2 answers:
Nookie1986 [14]3 years ago
6 0
Answer - There are three ways an object can accelerate: a change in velocity, a change in direction, or a change in both velocity and direction.
satela [25.4K]3 years ago
5 0

Answer:

change a velocity

Explanation:

kkfjfjdkdjcnfkdjxbcbdkgkg

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The density of gold is 19.3. G/cm(3). If a nugget of iron pyrite and nugget of gold each have a mass of 50 g, what can you concl
tangare [24]
The pyrite will be bigger, because its density is much lower.

I <em>do</em> know that the gold's volume will be 2.5906 (With a bunch more numbers after it)

50 divided by 19.3 = 2.5906
5 0
3 years ago
The reaction of magnesium ribbon with oxygen.what is the product formed?
zaharov [31]
When oxygen reacts with magnesium thenMgO3 is formed.

Mg +O2----> MgO3
6 0
3 years ago
Four solid plastic cylinders all have radius 2.55 cm and length 5.70 cm. Find the charge of each cylinder given the following ad
vazorg [7]

Answer:3

Explanation:idk

5 0
3 years ago
Does time stop in a black hole
lbvjy [14]

Answer:

In standard GR, nothing exists at the center of a black hole. The center of a black hole is a singularity, and because GR fails at that point it is simply removed from the manifold. That means that the singularity is not part of spacetime.

To answer your question more realistically, we believe that GR is an approximate theory that fails well before you reach the center. Unfortunately, we have no good alternative theory with which to answer the question in the region where GR fails. We simply don’t have any data from that regime and it is very hard to formulate a good theory without data. So there very well could be time at the center, but we simply don’t have a good way to even guess.

4 0
3 years ago
Read 2 more answers
4. A meter has a resistance of 100 Ω and gives a full scale deflection when it carries a current of 25 μA. (a) What resistor, Rx
frez [133]

Answer:

A=50mΩ

B≅50mΩ

Explanation:

A) To answer this question we have to use the Current Divider Rule. that rule says:

Ix=.\frac{Req}{Rx} *Itotal (1)

Itotal represents the new maximun current, 50mA, Ix is the current going through the 100 ohms resistor, and Req. is the equivalent resitor.

We now have a set of two resistor in parallel, so:

Req.=\frac{1}{\frac{1}{R1}+\frac{1}{R2}  } (2)

where R1 is the resitor we have to calculate, and R2 is the 100 ohms resistor (25 uA).

substituting and rearranging (2)

Req.=\frac{ 100*R1}{R1+100} (3)

Now substituting (3) in (1).

25*10^{-6} =\frac{\frac{ 100*R1}{R1+100}}{100} *50*10^{-3}

solving this, The value of R1 is: 50mΩ

This value of R1 will guaranty that the ammeter full reflection willl be at 50mA.

Given that R2 (100ohm) it too much bigger than 50mΩ, the equivalent resistor will tend to 50mΩ

If you substitude this values on (2) Req. will be 49.97 mΩ.

7 0
3 years ago
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