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user100 [1]
4 years ago
12

What is the ionosphere

Physics
1 answer:
ICE Princess25 [194]4 years ago
7 0
A ionosphere is a layer of the earths atmosphere that is ionized by solar and cosmic radiation <span />
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2. A powerful experimental sewing machine is powered by a mass-spring system. This
Alexus [3.1K]

We have that the Number of stitches per sec and he mass of  oscillation motion is mathematically given as

a) Nt=25stitches per sec

b) m=2.033e-5kg

<h3>Number of stitches per sec and he mass of  oscillation motion</h3>

Question Parameters:

This <u>sewing </u>machine is capable of stitching 1,500 stiches in one minute.

If the <em>sewing </em>machine has a spring constant of 0.5 N/m,

Generally the equation for the Number of stitches per sec  is mathematically given as

Nt=N/t

Therefore

Nt=1500/60

Nt=25stitches per sec

b)

Generally the equation for the Time t  is mathematically given as

T=2\pi\sqrt{\frac{m}{k}}

Therefore

0.04=2\pi\sqrt{\frac{m}{0.5}}\\\\m=\frac{0.5*0.04^2}{4\pi^2}

m=2.033e-5kg

For more information on Mass visit

brainly.com/question/15959704

7 0
2 years ago
The source of the earth’s magnetic field is found in the _____.
telo118 [61]
The source of the earth's magnetic field is found in the ;LIQUID MAGNETIZED IRON IN THE CORE OF THE EARTH. The earth's magnetic field is believed to be generated very deep down in the earth's core as a result of molten iron which it contains. 
5 0
3 years ago
Read 2 more answers
If the mass of an object is 44 kilograms and its velocity is 10 meters per second east, how much Kinetic Energy does it have?
olya-2409 [2.1K]
Given: Mass m = 44 Kg;      Velocity v = 10 m/s

Required: Kinetic energy K.E = ?

Formula: K.E = 1/2 mv²

               K.E 1/2 (44 Kg)(10 m/s)²

               K.E = 2,200 Kg.m²/s²

               K.E = 2,200 J Answer is A
8 0
3 years ago
Please someone help me !!
sergij07 [2.7K]

Answer:

D

Explanation:

because if the solvent is more than the solvent then we can't resolve it.

so our product will be suspended

6 0
3 years ago
A negative charge, q1, of 6 µC is 0. 002 m north of a positive charge, q2, of 3 µC. What is the magnitude and direction of the e
prohojiy [21]

Force on the particle is defined as the application of the force field of one particle on another particle. The magnitude and direction of the electrical force will be 4.05×10⁴N towards the north.

<h3>What is electrical force?</h3>

Force on the particle is defined as the application of the force field of one particle on another particle. It is a type of virtual force.

The given data in the problem is

q₁ is the negative charge = 6 µC=6×10⁻⁶ C

q₂ is the positive charge = 3 µC=3×10⁻⁶ C

r is the distance between the charges=0.002 m

F_E is the electric force =?

The value of electric force will be;

\rm F_E= \frac{Kq_1q_2}{r^2} \\\\ F_E= \frac{9\times 10^9\times 6\times 10^{-6}\times3\times10^{-6}}{(0.002)^2}\\\\ \rm F_E=4.05\times10^4\;N

Hence the magnitude and direction of the electrical force will be 4.05×10⁴N towards the north.

To learn more about the electrical force refer to the link;

brainly.com/question/1076352

7 0
2 years ago
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