What determines the amount of energy a substance has

1 answer:

3 0

If you think more specifically about energy,such as thermal energy,the amount of that energy a substance has is determined by the movement of the molecules.hope this helps u

You might be interested in

Why doesnt food have energy

Nataly_w [17]

Food has calories which feeds your bones in your body from eating away your muscles, it doesn’t have “energy” on the other hand pop and drinks do.

3 0

3 years ago

Read 2 more answers

A piece of blue paper appears blue because the paper

vfiekz [6]

A piece of blue paper appears blue because the paper absorbs all colors of light except blue. <em> (b)</em>

So any light that bounces off of the paper and enters your eye must be blue light !

6 0

2 years ago

ANswer the question and give example: Can friction ever perform positive work?

Harman [31]

Yes. Think of block sitting on top of a bigger block. If the bottom block moves, it will drag the top block with it. Since the force of friction on the small block and its displacement are in the same direction, the "work" is positive. The static friction is a passive force, It is not a source of energy; it transmits the force placed on the bottom block. (And the "work" done by the friction on the bottom block is exactly the negative of the work done on the top block.)

4 0

3 years ago

Read 2 more answers

Is the sun yellow or is it orange.

LiRa [457]

Answer:

But the Sun isn't actually yellow; it's just an illusion caused by the Earth's atmosphere. The powerful processes happening inside the Sun are so robust that it emits every color of light imaginable. Together, these colors form a pure white light, which is precisely what you'd see from space.

Hoped I helped

6 0

2 years ago

Read 2 more answers

A 3.0 m tall, 40 cm diameter concrete column supports a 235,000 kg load. by how much is the column compressed? assume young's mo

statuscvo [17]

The Young modulus E is given by:
$E= \frac{F L_0}{A \Delta L}$
where
F is the force applied
A is the cross-sectional area perpendicular to the force applied
$L_0$ is the initial length of the object
$\Delta L$ is the increase (or decrease) in length of the object.

In our problem, $L_0 = 3.0 m$ is the initial length of the column, $E=3.0 \cdot 10^{10}N/m^2$ is the Young modulus. We can find the cross-sectional area by using the diameter of the column. In fact, its radius is:
$r= \frac{d}{2}= \frac{40 cm}{2}=20 cm=0.2 m$
and the cross-sectional area is
$A=\pi r^2 = \pi (0.20 m)^2=0.126 m^2$
The force applied to the column is the weight of the load:
$W=mg=(235000 kg)(9.81 m/s^2)=2.305 \cdot 10^6 N$

Now we have everything to calculate the compression of the column:
$\Delta L = \frac{F L_0}{EA}= \frac{(2.305\cdot 10^6 N)(3.0 m)}{(3.0\cdot 10^{10}N/m^2)(0.126 m^2)} =1.83\cdot 10^{-3}m$
So, the column compresses by 1.83 millimeters.

3 0

3 years ago

Read 2 more answers