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Temka [501]
3 years ago
11

A graph with resistance in ohms on the x-axis from 0 to 200 and current in amps on the y-axis from 0 to 5. The graph is labeled

as current as a function of resistance at 50 V. Points are plotted at (10, 5), (20, 2.5), (100, .5) and (200, .25). There is an inverse curve through the points. Use the graph to answer the questions. Based on the graph, what happens to current as resistance increases? This type of graph shows which type of relationship between the two variables? What would be a reasonable estimate for current at a resistance of 50 Ω?
Physics
1 answer:
Dafna1 [17]3 years ago
5 0

Answer:

1. decreases

2. inverse proportionality

3. 1 A

Explanation

Just did it

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A mixture of helium and oxygen is used in scuba diving tanks to help prevent ""the bends"". 46 L helium and 12 L oxygen are comb
marin [14]

Answer

given,

For helium

Volume,V = 46 L

Pressure,P = 1 atm

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R=0.0821 L . atm /mole.K

n₁ = ?

number of moles

we know

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n_1 =\dfrac{46 \times 1}{0.0821\times 298}

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For oxygen

Volume,V = 12 L

Pressure,P = 1 atm

Temperature,T = 25°C  =  273 +25 = 298 K

R=0.0821 L . atm /mole.K

n₂ = ?

number of moles

we know

P V = n R T

n_2 =\dfrac{12 \times 1}{0.0821\times 298}

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Total volume of tank = 5 L

temperature of tank = 298 K

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P_1=\dfrac{n_1 R T}{V}

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Partial pressure of oxygen

P_2=\dfrac{n_2 R T}{V}

P_2=\dfrac{0.49\times 0.0821\times 298}{5}

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8 0
2 years ago
A sound has a sound level of 30 dB. Its intensity is what multiple of the standard reference level for intensities?
arsen [322]
<h2>Answer:</h2>

1000th multiple of the standard reference level for intensities.

<h2>Explanation:</h2>

The sound intensity level (β), measured in decibels, of a sound with an intensity of I is defined as follows;

β = 10 log (I / I₀)       --------------------(i)

Where;

I₀ = reference intensity

Given from the question;

β = sound level = 30dB

Substitute this value into equation (i) as follows;

30 = 10 log (I / I₀)

Divide both sides by 3;

3 = log (I / I₀)

Take antilog of both sides;

10^(3) = (I / I₀)

1000 = I / I₀

Solve for I;

I = 1000I₀

Therefore the intensity of the sound is 1000 times the standard reference level for intensities (I₀)

7 0
3 years ago
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