Complete question:
while hunting in a cave a bat emits sounds wave of frequency 39 kilo hartz were moving towards a wall with a constant velocity of 8.32 meters per second take the speed of sound as 340 meters per second. calculate the frequency reflected off the wall to the bat?
Answer:
The frequency reflected by the stationary wall to the bat is 41 kHz
Explanation:
Given;
frequency emitted by the bat, = 39 kHz
velocity of the bat,
= 8.32 m/s
speed of sound in air, v = 340 m/s
The apparent frequency of sound striking the wall is calculated as;
![f' = f(\frac{v}{v- v_b} )\\\\f' = 39,000(\frac{340}{340 -8.32} )\\\\f' = 39978.29 \ Hz](https://tex.z-dn.net/?f=f%27%20%3D%20f%28%5Cfrac%7Bv%7D%7Bv-%20v_b%7D%20%29%5C%5C%5C%5Cf%27%20%3D%2039%2C000%28%5Cfrac%7B340%7D%7B340%20-8.32%7D%20%29%5C%5C%5C%5Cf%27%20%3D%2039978.29%20%5C%20Hz)
The frequency reflected by the stationary wall to the bat is calculated as;
![f_s = f'(\frac{v + v_b}{v} )\\\\f_s = 39978.29(\frac{340 + 8.32}{340} )\\\\f_s = 40,956.56 \ Hz](https://tex.z-dn.net/?f=f_s%20%3D%20f%27%28%5Cfrac%7Bv%20%2B%20v_b%7D%7Bv%7D%20%29%5C%5C%5C%5Cf_s%20%3D%2039978.29%28%5Cfrac%7B340%20%2B%208.32%7D%7B340%7D%20%29%5C%5C%5C%5Cf_s%20%3D%2040%2C956.56%20%5C%20Hz)
![f_s\approx 41 \ kHz](https://tex.z-dn.net/?f=f_s%5Capprox%2041%20%5C%20kHz)
Answer:
Frequency = 3.0 Hertz
Explanation:
Given the following data;
Period = 0.333 seconds
To find the frequency;
Mathematically, frequency of a wave is given by the formula;
Frequency = 1/period
Substituting into the formula, we have;
Frequency = 1/0.333
Frequency = 3.0 Hertz
<span>Place a test charge in the middle. It is 2cm away from each charge.
The electric field E= F/Q where F is the force at the point and Q is the charge causing the force in this point.
The test charge will have zero net force on it. The left 30uC charge will push it to the right and the right 30uC charge will push it to the left. The left and right force will equal each other and cancel each other out.
THIS IS A TRICK QUESTION.
THe electric field exactly midway between them = 0/Q = 0.
But if the point moves even slightly you need the following formula
F= (1/4Piε)(Q1Q2/D^2)
Assume your test charge is positive and make sure you remember two positive charges repel, two unlike charges attract. Draw the forces on the test charge out as vectors and find the magnetude of the force, then divide by the total charge to to find the electric field strength:)</span>
All the boats operating at night requires Navigation light.
Navigation light helps prevent collisions between boats and see if visibility is poor. The types of boat are : Rowboats, Tug boats, Vessels, Sailboat etc.
Various boats have different lightning color to show its use and side of the boat.
In an extremely simplified explanation,
What happens is that the steam (heat) that is generated by the burning of coal is used to rotate the motor of the steam engine.