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Delvig [45]
3 years ago
13

Conductors such as metal are materials that have a

Chemistry
1 answer:
likoan [24]3 years ago
5 0

Answer:

Conductors allow a flow of current or a charge of flow

I hope this helped! Please rate it the brainlist if possible, thanks

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NH3 = 14 +3*1=17 g/mol
Mass = mol * molar mass = 0.687 * 17= 11.679 g
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Uranium has an atomic weight of 238 amu.
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Answer:

U= 238g/mol

U2O5= 556g/mol

Explanation:

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brainly.com/question/18996619?answering=true&answeringSource=feedPublic%2FhomePage%2F7

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brainly.com/question/18996619?answering=true&answeringSource=feedPublic%2FhomePage%2F7

brainly.com/question/18996619?answering=true&answeringSource=feedPublic%2FhomePage%2F7

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Read 2 more answers
Purification of copper can be achieved by electrorefining copper from an impure copper anode onto a pure copper cathode in an el
givi [52]

Answer: The amount of time needed to plate 14.0 kg of copper onto the cathode is 295 hours

Explanation:

We are given:

Moles of electron = 1 mole

According to mole concept:

1 mole of an atom contains 6.022\times 10^{23} number of particles.

We know that:

Charge on 1 electron = 1.6\times 10^{-19}C

Charge on 1 mole of electrons = 1.6\times 10^{-19}\times 6.022\times 10^{23}=96500C

Cu^{2+}+2e^-\rightarrow Cu

2\times 96500=193000C is passed to deposit = 1 mole of copper

63.5 g of copper is deposited by = 193000 C

14\times 1000g=14000g of copper is deposited by =\frac{193000}{63.5}\times 14000=42551181 C

To calculate the time required, we use the equation:

I=\frac{q}{t}

where,

I = current passed = 40.0 A

q = total charge = 42551181 C

t = time required = ?

Putting values in above equation, we get:

40.0=\frac{42551181 C}{t}\\\\t=1063779sec

Converting this into hours, we use the conversion factor:

1 hr = 3600 seconds

So, 1063779s\times \frac{1hr}{3600s}=295hr

Hence, the amount of time needed to plate 14.0 kg of copper onto the cathode is 295 hours

3 0
3 years ago
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