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3 years ago

13

A 3.6-kg chihuahua charges at a speed of 3.3m/s. what is the magnitude of the average force needed to bring the chihuahua to a s

top in 0.50s?

1 answer:

Over [174]3 years ago

5 0

...
<span>use this equation </span>
<span>F delta(t) = m delta(v) </span>
<span>F (0.50) = 3.6 (3.3) </span>
<span>F = 23.8 N </span>

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