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kondaur [170]
3 years ago
7

A _________ engine operates using a three-sided metal rotor instead of the traditional piston-and-cylinder arrangement.

Physics
1 answer:
postnew [5]3 years ago
5 0

That's a description of what makes the "Wankel engine" unique.

When it first came to the USA market, it came as the guts of a
new brand of car . . . the Mazda.  I don't know if some, or all, or
none of today's Mazdas still use the Wankel 'rotary' engine.
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Uma massa de 500 Kg desloca-se com velocidade 58 km por hora. Calcule o módulo de sua quantidade por movimento
Simora [160]

The momentum of the object is 8050 kg m/s

Explanation:

The momentum of an object is defined as

p=mv

where

p is the momentum

m is the mass

v is the velocity of the object

For the object in this problem, we have

m = 500 kg is its mass

v = 58 km/h is its velocity

Converting the velocity into m/s,

v=58 \frac{km}{h}\cdot \frac{1000 m/km}{3600 s/h}=16.1 m/s

Therefore now we can find the momentum of the object:

p=(500)(16.1)=8050 kg m/s

Learn more about momentum:

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7 0
3 years ago
What percentage of energy consumed in the united states is nonrenewable??
IgorLugansk [536]
It was estimated, according to the United States Energy Information Administration, that the United States still consumes almost 91% of non-renewable resources as its energy source. In addition, 32 % of it are natural gas, 28 % for petroleum and crude oil, and 21 % for coal power.
6 0
3 years ago
Definition of fluoresence
denis23 [38]

Answer:

the property of absorbing light of short wavelength and emitting light of longer wavelength.

Explanation:

YW

4 0
3 years ago
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An object is pulled with two forces, 10 N northward and 15 N southward. The direction of the net force is to the An object is pu
ValentinkaMS [17]

Answer:

check image

Explanation:

For any question related to newons law of motion first draw the free body diagram(FBD),

7 0
3 years ago
1) A boy drags a wooden crate with a mass of 20 kg, a distance of 12 m, across a rough level floor at a constant speed of 1.5 m/
mojhsa [17]

Answer: a) 49.560 and 21.13 b) i) 50 N, ii) 196 N iii) 196 N iv) 47.685 N

c) i) 594.72 ii) 0 iii) 0 iv) 0

d) 594.72

Explanation: question a)

The force is inclined at an angle of 25° to the horizontal

The horizontal component of force = 50 cos 25° = 49.560 N

The vertical component of force = 50 sin 30°= 21.130N

Question b)

i) according to the question applied force is 50 N

ii) if g = 9.8m/s², w=mg where m = mass of object = 20kg hence weight = 20* 9.8 = 196 N

iii) the normal force is the force the floor exerts on the body as a result of the weight of the object.

Normal reaction R = W = mg, we already deduced that w = mg, hence R = 196 N.

iv) according to newton's laws of motion

F - Fr = ma

F = applied force = horizontal component of force = 49.560 N.

We need to get the acceleration (a) by using Newton laws of motion before we can be able to compute the frictional force..

The body started from rest hence initial velocity u = 0

Final velocity v = 1.5m/s distance covered (s) = 12m

v ² = u² + 2as

But u = 0

v² = 2as

1.5² = 2(a) * 12

2.25 = 24a

a = 2.25/24 = 0.09735m/s²

From F - Fr = ma

49.560 - Fr = 20 * 0.09735

49.560 - Fr = 1.875

Fr = 49.560 - 1.875

Fr = 47.685 N

Question c)

i) The applied force = 49.560 N, distance covered = 12m

Work done = force * distance

Work done = 49.560 * 12

Work done = 594.72 J

ii) the weight of the object does not make the object move a distance, hence work done = 0 ( since distance covered is 0)

iii) the normal force is the same thing as the weight and they did not cover any distance hence work done is zero.

iv) the frictional force does not cover any distance, hence work done is zero.

Question d)

The total work done = work done by applied force + work done by weight + work done by normal reaction + work done by frictional force.

Total work done = 594.72 + 0 + 0 + 0 = 594.72 J

8 0
3 years ago
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